| # | Time | Username | Problem | Language | Result | Execution time | Memory | 
|---|---|---|---|---|---|---|---|
| 841640 | Enchom | 참나무 (IOI23_beechtree) | C++17 | 3 ms | 15356 KiB | 
This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include "beechtree.h"
#include <bits/stdc++.h>
#define all(x) (x).begin(), (x).end()
#define xx first
#define yy second
using namespace std;
typedef pair<int, int> pii;
const int N = 2e5 + 1;
struct Graph
{
    int cnt[N];
    bool con[N];
    vector<pii> srt[N];
    map<int, vector<int>> col[N];
} graph;
bool check(int v, int u, bool equalStuff)
{
    for (auto &pr : graph.col[v])
    {
        auto &[col, vec] = pr;
        auto it = graph.col[u].find(col);
        if (it == graph.col[u].end() || (!equalStuff && graph.cnt[vec[0]] > graph.cnt[it->yy[0]]))
        {
            return false;
        }
    }
    return true;
}
int dfs(int u)
{
    graph.cnt[u] = 1;
    graph.con[u] = true;
    for (auto &pr : graph.col[u])
    {
        auto &[col, vec] = pr;
        graph.con[u] &= vec.size() == 1;
        for (int v : vec)
        {
            int cnv = dfs(v);
            if (cnv == -1)
            {
                graph.con[u] = false;
            }
            else
            {
                graph.cnt[u] += cnv;
            }
            for (pii p : graph.srt[v])
            {
                graph.srt[u].push_back(p);
            }
        }
    }
    graph.srt[u].push_back({graph.cnt[u], u});
    sort(all(graph.srt[u]));
    for (int i = 0; i < graph.srt[u].size() - 1; ++i)
    {
        for (int j = i + 1; j < graph.srt[u].size() - 1; j++)
        {
            graph.con[u] = graph.con[u] & check(graph.srt[u][i].yy, graph.srt[u][j].yy, false);
        }
    }
    return graph.con[u] ? graph.cnt[u] : -1;
}
vector<int> beechtree(int n, int m, vector<int> P, vector<int> C)
{
    for (int i = 1; i < n; ++i)
    {
        int p = P[i];
        int c = C[i];
        if (!graph.col[p].count(c))
        {
            graph.col[p][c] = vector<int>();
        }
        graph.col[p][c].push_back(i);
    }
    dfs(0);
    vector<int> ans;
    for (int i = 0; i < n; ++i)
        ans.push_back(graph.con[i]);
    return ans;
}
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