Submission #84092

#TimeUsernameProblemLanguageResultExecution timeMemory
84092alextodoranMaxcomp (info1cup18_maxcomp)C++14
100 / 100
198 ms71436 KiB
#include <bits/stdc++.h> #define NM 1002 using namespace std; int n, m; int ma[NM][NM]; int mx1[NM][NM], mx2[NM][NM], mx3[NM][NM], mx4[NM][NM], mx = -1; int main() { ios_base::sync_with_stdio(false); cin.tie(nullptr); cout.tie(nullptr); cin >> n >> m; for(int i = 1; i <= n; i++) { for(int j = 1; j <= m; j++) { cin >> ma[i][j]; mx1[i][j] = max(max(mx1[i - 1][j], mx1[i][j - 1]) - 1, ma[i][j] - 1); } for(int j = m; j >= 1; j--) mx2[i][j] = max(max(mx2[i - 1][j], mx2[i][j + 1]) - 1, ma[i][j] - 1); } for(int i = n; i >= 1; i--) { for(int j = 1; j <= m; j++) mx3[i][j] = max(max(mx3[i + 1][j], mx3[i][j - 1]) - 1, ma[i][j] - 1); for(int j = m; j >= 1; j--) mx4[i][j] = max(max(mx4[i + 1][j], mx4[i][j + 1]) - 1, ma[i][j] - 1); } for(int i = 1; i <= n; i++) for(int j = 1; j <= m; j++) mx = max(mx, max(max(mx1[i][j], mx2[i][j]), max(mx3[i][j], mx4[i][j])) - ma[i][j]); cout << mx << "\n"; return 0; }
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