제출 #839854

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
839854		Yongaron	Soccer Stadium (IOI23_soccer)	C++17	1.50 / 100	298 ms	32332 KiB

soccer

#include "soccer.h"
#include <bits/stdc++.h>

using namespace std;

int biggest_stadium(int N, vector<vector<int>> F)
{
    bool good = true;
    for (int i = 0; i < N && good; i++)
    {
        bool seen0 = false;
        bool seen1 = false;
        for(int j = 0; j < N; j++)
        {
            if (seen1 && !F[i][j])
            {
                good = false;
                break;
            }
            if (seen0 && F[i][j])
            {
                seen1 = true;
            }
            if(!F[i][j])
            {
                seen0 = true;
            }
        }
    }
    for(int j = 0; j < N && good; j++)
    {
        bool seen0 = false;
        bool seen1 = false;
        for(int i = 0; i < N; i++)
        {
            if (seen1 && !F[i][j])
            {
                good = false;
                break;
            }
            if (seen0 && F[i][j])
            {
                seen1 = true;
            }
            if(!F[i][j])
            {
                seen0 = true;
            }
        }
    }

    vector<vector<bool>> visited(N, vector<bool>(N, false));
    queue<pair<int, int>> q;
    int vis = 0;

    for(int i = 0; i < N && q.empty(); i++)
    {
        for(int j = 0; j < N && q.empty(); j++)
        {
            if(!F[i][j])
            {
                q.push({i, j});
                visited[i][j] = true;
                vis = 1;
            }
        }
    }

    vector<int> dx = {0, 0, 1, -1};
    vector<int> dy = {1, -1, 0, 0};

    while(!q.empty())
    {
        auto [i, j] = q.front();
        q.pop();
        for (int k = 0; k < 4; k++)
        {
            int ni = i + dx[k];
            int nj = j + dy[k];
            if (ni < 0 || ni >= N || nj < 0 || nj >= N || visited[ni][nj] || F[ni][nj])
                continue;
            visited[ni][nj] = true;
            vis++;
            q.push({ni, nj});
        }
    }

    int empty = 0;
    for(int i = 0; i < N; i++)
    {
        for(int j = 0; j < N; j++) {
            if(!F[i][j])
                empty++;
        }
    }

    if (vis != empty)
        good = false;

    if (good)
        return empty;
    else
        return 0;
}

• Subtask 0: 0 / 0
• Subtask 1: 1.5 / 6
• Subtask 2: 0 / 8
• Subtask 3: 0 / 22
• Subtask 4: 0 / 18
• Subtask 5: 0 / 16
• Subtask 6: 0 / 30