# | 제출 시각UTC-0 | 아이디 | 문제 | 언어 | 결과 | 실행 시간 | 메모리 |
---|---|---|---|---|---|---|---|
839710 | model_code | 봉쇄 시간 (IOI23_closing) | C++17 | 1081 ms | 141612 KiB |
이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
// correct/solution-ayaze-brute-linear-knapsack.cpp
// O(N^3)
#include "closing.h"
#include <bits/stdc++.h>
using namespace std;
const int kVisited = 1;
const int kTypeSingle = 1, kTypeBoth = 2;
const long long kInf = 4e18;
vector<vector<pair<int, int>>> adj_list;
vector<long long> dist_from_x, dist_from_y;
void DfsDistance(int now, int prv, long long current_dist, vector<long long> &dist_vec, vector<int> &parent)
{
dist_vec[now] = current_dist;
parent[now] = prv;
for (pair<int, int> edge : adj_list[now])
{
int nxt = edge.first;
if (nxt == prv)
continue;
long long new_dist = edge.second + current_dist;
DfsDistance(nxt, now, new_dist, dist_vec, parent);
}
}
void DfsComponent(int now, vector<int> &component, vector<int> &state)
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