제출 #838466

#제출 시각아이디문제언어결과실행 시간메모리
838466MathandskiRobot (JOI21_ho_t4)C++17
100 / 100
931 ms85372 KiB
#include <bits/stdc++.h> using namespace std; #define pb push_back #define is insert #define ll long long #define V vector #define MS multiset #define PL pair<ll, ll> #define F first #define S second #define PQ priority_queue #define f0r(i, begin, end) for (ll i = begin; i < end; i ++) #define For(i, end, begin) for (ll i = end; i > begin; i --) #define all(x) x.begin(), x.end() #define INF 1000000000000000000 #define inf 1000000000 #define MOD 1000000007 #define len(x) (ll)x.size() #define fileread(file) ifstream fin; fin.open((string)file + ".in"); ofstream fout; fout.open((string)file + ".out") #define fastio ios_base::sync_with_stdio(0LL); cin.tie(nullptr) template<typename T> istream& operator>>(istream& in, V<T>& a) {for(auto &x : a) in >> x; return in;}; template<typename T> ostream& operator<<(ostream& out, V<T>& a) {for(auto &x : a) out << x << ' '; return out;}; const ll MAX_N = 1e5 + 3 ; ll N, M; map<ll, V<PL>> conn[MAX_N]; map<ll, ll> psum[MAX_N]; ll dp[MAX_N]; map<ll, ll> dp2[MAX_N]; int main () { cin >> N >> M; f0r (i, 0, M) { ll a, b, c, d; cin >> a >> b >> c >> d; a --; b --; conn[a][c].pb({b, d}); conn[b][c].pb({a, d}); psum[a][c] += d; psum[b][c] += d; } f0r (i, 0, N) { dp[i] = INF; } using T = tuple<ll, ll, ll>; priority_queue<T, vector<T>, greater<T>> pq; dp[0] = 0; pq.push({0, 0, -1}); while (pq.size()) { ll cdist, node, prev; tie(cdist, node, prev) = pq.top(); pq.pop(); if (prev != -1) { if (dp2[node][prev] != cdist) continue; for (auto p : conn[node][prev]) { ll case1 = psum[node][prev] - p.S + cdist; if (case1 < dp[p.F]) { pq.push({dp[p.F] = case1, p.F, -1}); } } } else { if (cdist != dp[node]) continue; for (auto i : conn[node]) { for (auto p : i.S) { ll case1 = min(psum[node][i.F] - p.S, p.S) + cdist; if (case1 < dp[p.F]) { pq.push({dp[p.F] = case1, p.F, -1}); } ll case2 = cdist; if (dp2[p.F].find(i.F) == dp2[p.F].end()) { pq.push({dp2[p.F][i.F] = case2, p.F, i.F}); } else if (case2 < dp2[p.F][i.F]) { pq.push({dp2[p.F][i.F] = case2, p.F, i.F}); } } } } } if (dp[N - 1] == INF) { cout << -1 << endl; } else { cout << dp[N - 1] << endl; } }
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