oj.uz

답안 #836011

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
836011 2023-08-24T04:55:58 Z maomao90 식물 비교 (IOI20_plants) C++17
44 / 100
 1031 ms 29596 KB 
// I can do all things through Christ who strengthens me
// Philippians 4:13

#include "plants.h"
#include <bits/stdc++.h>
using namespace std;

#define REP(i, j, k) for (int i = j; i < (k); i++)
#define RREP(i, j, k) for (int i = j; i >= (k); i--)

template <class T>
inline bool mnto(T &a, const T b) {return a > b ? a = b, 1 : 0;}
template <class T>
inline bool mxto(T &a, const T b) {return a < b ? a = b, 1 : 0;}

typedef long long ll;
typedef long double ld;
#define FI first
#define SE second
typedef pair<int, int> ii;
typedef pair<ll, ll> pll;
#define ALL(x) x.begin(), x.end()
#define SZ(x) (int) x.size()
#define pb push_back
typedef vector<int> vi;
typedef vector<ll> vll;
typedef vector<ii> vii;
typedef tuple<int, int, int> iii;
typedef vector<iii> viii;

#ifndef DEBUG
#define cerr if (0) cerr
#endif

const int INF = 1000000005;
const ll LINF = 1000000000000000005;
const int MAXN = 200005;

int n, k;
vi r;
int bad[MAXN];
bool vis[MAXN];
int h[MAXN];

#define MLR int mid = (lo + hi) >> 1, lc = u << 1, rc = u << 1 ^ 1
struct SegTree {
    pair<ii, int> mx[MAXN * 4];
    ii lz[MAXN * 4];
    void init(int u = 1, int lo = 0, int hi = n - 1) {
        lz[u] = {0, 0};
        if (lo == hi) {
            mx[u] = {{r[lo], 0}, lo};
            return;
        }
        MLR;
        init(lc, lo, mid);
        init(rc, mid + 1, hi);
        mx[u] = max(mx[lc], mx[rc]);
    }
    void apply(ii x, int u, int lo, int hi) {
        mx[u].FI.FI += x.FI;
        mx[u].FI.SE += x.SE;
        lz[u].FI += x.FI;
        lz[u].SE += x.SE;
    }
    void propo(int u, int lo, int hi) {
        if (lz[u] == ii(0, 0)) {
            return;
        }
        MLR;
        apply(lz[u], lc, lo, mid);
        apply(lz[u], rc, mid + 1, hi);
        lz[u] = {0, 0};
    }
    void incre(int s, int e, ii x, int u = 1, int lo = 0, int hi = n - 1) {
        if (s >= n) {
            incre(s - n, e - n, x);
            return;
        }
        if (e >= n) {
            incre(s, n - 1, x);
            incre(0, e - n, x);
            return;
        }
        if (lo >= s && hi <= e) {
            apply(x, u, lo, hi);
            return;
        }
        MLR;
        propo(u, lo, hi);
        if (s <= mid) {
            incre(s, e, x, lc, lo, mid);
        }
        if (e > mid) {
            incre(s, e, x, rc, mid + 1, hi);
        }
        mx[u] = max(mx[lc], mx[rc]);
    }
    pair<ii, int> qmx(int s, int e, int u = 1, int lo = 0, int hi = n - 1) {
        if (s >= n) {
            return qmx(s - n, e - n);
        }
        if (e >= n) {
            return max(qmx(s, n - 1), qmx(0, e - n));
        }
        if (lo >= s && hi <= e) {
            return mx[u];
        }
        MLR;
        propo(u, lo, hi);
        pair<ii, int> res = {{-INF, -INF}, -INF};
        if (s <= mid) {
            mxto(res, qmx(s, e, lc, lo, mid));
        }
        if (e > mid) {
            mxto(res, qmx(s, e, rc, mid + 1, hi));
        }
        return res;
    }
} st1, st2;

struct DSU {
    int p[MAXN], rnk[MAXN];
    void init() {
        REP (i, 0, n) {
            p[i] = i;
            rnk[i] = 0;
        }
    }
    int findp(int i) {
        if (p[i] == i) {
            return i;
        }
        return p[i] = findp(p[i]);
    }
    bool join(int a, int b) {
        int pa = findp(a), pb = findp(b);
        if (pa == pb) {
            return 0;
        }
        if (rnk[pa] < rnk[pb]) {
            swap(pa, pb);
        }
        if (rnk[pa] == rnk[pb]) {
            rnk[pa]++;
        }
        p[pb] = pa;
        return 1;
    }
} ds1, ds2;

void init(int _k, vi _r) {
    k = _k; r = _r;
    n = SZ(r);
    st1.init();
    st2.init();
    ds1.init();
    ds2.init();
    REP (i, 0, n) {
        if (r[i] == k - 1) {
            st1.incre(i + 1, i + k - 1, {0, -1});
            st2.incre(i, i, {-INF, -INF});
        }
    }
    int z = 1;
    while (1) {
        vi todo;
        while (1) {
            auto [tmp, id] = st1.qmx(0, n - 1);
            if (tmp != ii(k - 1, 0)) {
                break;
            }
            cerr << id << ' ' << z << '\n';
            h[id] = z;
            st1.incre(id, id, {-INF, -INF});
            todo.pb(id);
            if (k == 2 || n <= 300) {
                REP (j, id + 1, id + k) {
                    if (h[j] == 0) {
                        ds1.join(id, j % n);
                    } else {
                        ds2.join(id, j % n);
                    }
                }
            }
        }
        if (todo.empty()) {
            break;
        }
        for (int id : todo) {
            st1.incre(id + 1, id + k - 1, {0, 1});
            st1.incre(id - k + 1 + n, id - 1 + n, {1, 0});
            st2.incre(id - k + 1 + n, id - 1 + n, {1, 0});
            auto [v, u] = st2.qmx(id - k + 1 + n, id - 1 + n);
            while (v.FI == k - 1) {
                st1.incre(u + 1, u + k - 1, {0, -1});
                st2.incre(u, u, {-INF, -INF});
                tie(v, u) = st2.qmx(id - k + 1 + n, id - 1 + n);
            }
        }
        z++;
    }
	return;
}

int compare_plants(int x, int y) {
    if (k == 2 && ds1.findp(x) != ds1.findp(y) && ds2.findp(x) != ds2.findp(y)) {
        return 0;
    } else if (h[x] > h[y]) {
        return 1;
    } else {
        return -1;
    }
}

Subtask #1
0 / 5.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 340 KB Output is correct
2 Correct 0 ms 340 KB Output is correct
3 Correct 0 ms 340 KB Output is correct
4 Incorrect 0 ms 340 KB Output isn't correct
5 Halted 0 ms 0 KB -

Subtask #2
14.0 / 14.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 340 KB Output is correct
2 Correct 0 ms 340 KB Output is correct
3 Correct 0 ms 340 KB Output is correct
4 Correct 0 ms 340 KB Output is correct
5 Correct 1 ms 340 KB Output is correct
6 Correct 4 ms 468 KB Output is correct
7 Correct 56 ms 3964 KB Output is correct
8 Correct 2 ms 340 KB Output is correct
9 Correct 4 ms 488 KB Output is correct
10 Correct 55 ms 3960 KB Output is correct
11 Correct 51 ms 3844 KB Output is correct
12 Correct 51 ms 4012 KB Output is correct
13 Correct 55 ms 3952 KB Output is correct

Subtask #3
13.0 / 13.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 340 KB Output is correct
2 Correct 0 ms 340 KB Output is correct
3 Correct 0 ms 340 KB Output is correct
4 Correct 0 ms 340 KB Output is correct
5 Correct 1 ms 340 KB Output is correct
6 Correct 4 ms 468 KB Output is correct
7 Correct 56 ms 3964 KB Output is correct
8 Correct 2 ms 340 KB Output is correct
9 Correct 4 ms 488 KB Output is correct
10 Correct 55 ms 3960 KB Output is correct
11 Correct 51 ms 3844 KB Output is correct
12 Correct 51 ms 4012 KB Output is correct
13 Correct 55 ms 3952 KB Output is correct
14 Correct 111 ms 6328 KB Output is correct
15 Correct 1031 ms 29476 KB Output is correct
16 Correct 112 ms 6348 KB Output is correct
17 Correct 1012 ms 29480 KB Output is correct
18 Correct 599 ms 29432 KB Output is correct
19 Correct 591 ms 29472 KB Output is correct
20 Correct 848 ms 29424 KB Output is correct

Subtask #4
17.0 / 17.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 340 KB Output is correct
2 Correct 0 ms 340 KB Output is correct
3 Correct 45 ms 3312 KB Output is correct
4 Correct 443 ms 29476 KB Output is correct
5 Correct 629 ms 29596 KB Output is correct
6 Correct 813 ms 29476 KB Output is correct
7 Correct 963 ms 29572 KB Output is correct
8 Correct 1016 ms 29532 KB Output is correct
9 Correct 591 ms 29508 KB Output is correct
10 Correct 521 ms 29508 KB Output is correct
11 Correct 357 ms 29476 KB Output is correct
12 Correct 407 ms 29420 KB Output is correct
13 Correct 629 ms 29516 KB Output is correct

Subtask #5
0 / 11.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 384 KB Output is correct
2 Correct 0 ms 340 KB Output is correct
3 Incorrect 0 ms 340 KB Output isn't correct
4 Halted 0 ms 0 KB -

Subtask #6
0 / 15.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 340 KB Output is correct
2 Correct 1 ms 340 KB Output is correct
3 Incorrect 0 ms 340 KB Output isn't correct
4 Halted 0 ms 0 KB -

Subtask #7
0 / 25.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 340 KB Output is correct
2 Correct 0 ms 340 KB Output is correct
3 Correct 0 ms 340 KB Output is correct
4 Incorrect 0 ms 340 KB Output isn't correct
5 Halted 0 ms 0 KB -