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답안 #835949

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
835949 2023-08-24T00:34:02 Z maomao90 슈퍼트리 잇기 (IOI20_supertrees) C++17
19 / 100
 162 ms 28120 KB 
// I can do all things through Christ who strengthens me
// Philippians 4:13

#include "supertrees.h"
#include <bits/stdc++.h>
using namespace std;

#define REP(i, j, k) for (int i = j; i < (k); i++)
#define RREP(i, j, k) for (int i = j; i >= (k); i--)

template <class T>
inline bool mnto(T &a, const T b) {return a > b ? a = b, 1 : 0;}
template <class T>
inline bool mxto(T &a, const T b) {return a < b ? a = b, 1 : 0;}

typedef long long ll;
typedef long double ld;
#define FI first
#define SE second
typedef pair<int, int> ii;
typedef pair<ll, ll> pll;
#define ALL(x) x.begin(), x.end()
#define SZ(x) (int) x.size()
#define pb push_back
typedef vector<int> vi;
typedef vector<ll> vll;
typedef vector<ii> vii;
typedef tuple<int, int, int> iii;

#ifndef DEBUG
#define cerr if (0) cerr
#endif

const int INF = 1000000005;
const ll LINF = 1000000000000000005;
const int MAXN = 1005;

int n;
vector<vi> g;
vector<vi> ans;
bool vis[MAXN];

bool incyc[MAXN];
bool solve(vi comp) {
    if (SZ(comp) == 1) {
        return 1;
    }
    vi cyc, line;
    for (int i : comp) {
        bool all2 = 1;
        for (int j : comp) {
            if (i == j) {
                continue;
            }
            if (g[i][j] != 2) {
                all2 = 0;
                break;
            }
        }
        if (all2) {
            cyc.pb(i);
            incyc[i] = 1;
        } else {
            line.pb(i);
        }
    }
    for (int i : line) {
        for (int j : comp) {
            if (j == i) {
                continue;
            }
            if (incyc[j]) {
                if (g[i][j] != 2) {
                    return 0;
                }
            } else {
                if (g[i][j] != 1) {
                    return 0;
                }
            }
        }
    }
    if (SZ(cyc) <= 1) {
        return 0;
    }
    if (line.empty()) {
        if (SZ(cyc) <= 2) {
            return 0;
        }
        REP (i, 0, SZ(cyc)) {
            ans[cyc[i]][cyc[(i + 1) % SZ(cyc)]] = 1;
            ans[cyc[(i + 1) % SZ(cyc)]][cyc[i]] = 1;
        }
        return 1;
    }
    REP (i, 0, SZ(line) - 1) {
        ans[line[i]][line[i + 1]] = 1;
        ans[line[i + 1]][line[i]] = 1;
    }
    REP (i, 0, SZ(cyc) - 1) {
        ans[cyc[i]][cyc[i + 1]] = 1;
        ans[cyc[i + 1]][cyc[i]] = 1;
    }
    ans[line[0]][cyc[0]] = 1;
    ans[cyc[0]][line[0]] = 1;
    ans[line[0]][cyc.back()] = 1;
    ans[cyc.back()][line[0]] = 1;
    return 1;
}

int construct(vector<vi> p) {
    n = SZ(p);
    ans = vector<vi>(n, vi(n, 0));
    g = p;
    REP (i, 0, n) {
        REP (j, 0, n) {
            if (g[i][j] == 3) {
                return 0;
            }
        }
    }
    REP (i, 0, n) {
        if (vis[i]) {
            continue;
        }
        vi comp;
        REP (j, 0, n) {
            if (g[i][j]) {
                comp.pb(j);
            }
        }
        for (int j : comp) {
            vis[j] = 1;
            REP (k, 0, n) {
                if ((g[j][k] > 0) != (g[i][k] > 0)) {
                    return 0;
                }
            }
        }
        if (!solve(comp)) {
            return 0;
        }
    }
    build(ans);
    return 1;
}

Subtask #1
0 / 11.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 212 KB Output is correct
2 Incorrect 1 ms 212 KB Answer gives possible 0 while actual possible 1
3 Halted 0 ms 0 KB -

Subtask #2
0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 212 KB Output is correct
2 Incorrect 1 ms 212 KB Answer gives possible 0 while actual possible 1
3 Halted 0 ms 0 KB -

Subtask #3
19.0 / 19.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 212 KB Output is correct
2 Correct 0 ms 336 KB Output is correct
3 Correct 1 ms 212 KB Output is correct
4 Correct 0 ms 212 KB Output is correct
5 Correct 1 ms 212 KB Output is correct
6 Correct 1 ms 212 KB Output is correct
7 Correct 1 ms 212 KB Output is correct
8 Correct 7 ms 1364 KB Output is correct
9 Correct 154 ms 27920 KB Output is correct
10 Correct 1 ms 212 KB Output is correct
11 Correct 1 ms 212 KB Output is correct
12 Correct 7 ms 1364 KB Output is correct
13 Correct 157 ms 27892 KB Output is correct
14 Correct 1 ms 212 KB Output is correct
15 Correct 1 ms 212 KB Output is correct
16 Correct 3 ms 980 KB Output is correct
17 Correct 66 ms 17960 KB Output is correct
18 Correct 1 ms 212 KB Output is correct
19 Correct 0 ms 212 KB Output is correct
20 Correct 0 ms 212 KB Output is correct
21 Correct 38 ms 7224 KB Output is correct
22 Correct 156 ms 28120 KB Output is correct
23 Correct 156 ms 27852 KB Output is correct
24 Correct 161 ms 27920 KB Output is correct
25 Correct 62 ms 17996 KB Output is correct
26 Correct 63 ms 18040 KB Output is correct
27 Correct 152 ms 27928 KB Output is correct
28 Correct 162 ms 27980 KB Output is correct
29 Correct 63 ms 17996 KB Output is correct

Subtask #4
0 / 35.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 212 KB Output is correct
2 Correct 1 ms 212 KB Output is correct
3 Incorrect 0 ms 212 KB Answer gives possible 0 while actual possible 1
4 Halted 0 ms 0 KB -

Subtask #5
0 / 21.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 212 KB Output is correct
2 Incorrect 1 ms 212 KB Answer gives possible 0 while actual possible 1
3 Halted 0 ms 0 KB -

Subtask #6
0 / 4.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 212 KB Output is correct
2 Incorrect 1 ms 212 KB Answer gives possible 0 while actual possible 1
3 Halted 0 ms 0 KB -