Submission #835234

#TimeUsernameProblemLanguageResultExecution timeMemory
835234GrindMachineLottery (CEOI18_lot)C++17
0 / 100
2 ms1748 KiB
// Om Namah Shivaya #include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> using namespace std; using namespace __gnu_pbds; template<typename T> using Tree = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>; typedef long long int ll; typedef long double ld; typedef pair<int, int> pii; typedef pair<ll, ll> pll; #define fastio ios_base::sync_with_stdio(false); cin.tie(NULL) #define pb push_back #define endl '\n' #define sz(a) a.size() #define setbits(x) __builtin_popcountll(x) #define ff first #define ss second #define conts continue #define ceil2(x, y) ((x + y - 1) / (y)) #define all(a) a.begin(), a.end() #define rall(a) a.rbegin(), a.rend() #define yes cout << "Yes" << endl #define no cout << "No" << endl #define rep(i, n) for(int i = 0; i < n; ++i) #define rep1(i, n) for(int i = 1; i <= n; ++i) #define rev(i, s, e) for(int i = s; i >= e; --i) #define trav(i, a) for(auto &i : a) template<typename T> void amin(T &a, T b) { a = min(a, b); } template<typename T> void amax(T &a, T b) { a = max(a, b); } #ifdef LOCAL #include "debug.h" #else #define debug(x) 42 #endif /* */ const int MOD = 1e9 + 7; const int N = 1e5 + 5; const int inf1 = int(1e9) + 5; const ll inf2 = ll(1e18) + 5; void solve(int test_case) { int n,l; cin >> n >> l; vector<int> a(n); rep(i,n) cin >> a[i]; int q; cin >> q; vector<int> queries(q); rep(i,q) cin >> queries[i]; auto b = queries; sort(all(b)); b.resize(unique(all(b))-b.begin()); int siz = sz(b); vector<int> nxt(l+1,inf1); rep(i,siz) nxt[b[i]] = i; rev(i,l-1,0) amin(nxt[i],nxt[i+1]); vector<vector<int>> pref(n,vector<int>(siz)); vector<int> dp(n+1); rep1(d,n){ // d = j-i fill(all(dp),0); rev(i,n-d-1,0){ int j = i+d; dp[i] = (a[i]!=a[j]) + dp[i+1]; } rep(i,n-d){ int j = i+d; if(j+l-1 >= n) break; int k = dp[i]-dp[i+l]; int ck = nxt[k]; pref[i][ck]++; pref[j][ck]++; } } rep(i,n){ rep1(j,siz-1){ pref[i][j] += pref[i][j-1]; } } rep(id,q){ int k = queries[id]; int ck = nxt[k]; rep(i,n){ if(i+l-1 >= n) break; int ans = pref[i][ck]; cout << ans << " "; } cout << endl; } } int main() { fastio; int t = 1; // cin >> t; rep1(i, t) { solve(i); } return 0; }
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