// Hallelujah, praise the one who set me free
// Hallelujah, death has lost its grip on me
// You have broken every chain, There's salvation in your name
// Jesus Christ, my living hope
#include <bits/stdc++.h>
using namespace std;
#define REP(i, s, e) for (int i = (s); i < (e); i++)
#define RREP(i, s, e) for (int i = (s); i >= (e); i--)
template <class T>
inline bool mnto(T& a, T b) {return a > b ? a = b, 1 : 0;}
template <class T>
inline bool mxto(T& a, T b) {return a < b ? a = b, 1: 0;}
typedef unsigned long long ull;
typedef long long ll;
typedef long double ld;
#define FI first
#define SE second
typedef pair<int, int> ii;
typedef pair<ll, ll> pll;
typedef tuple<int, int, int> iii;
#define ALL(_a) _a.begin(), _a.end()
#define SZ(_a) (int) _a.size()
#define pb push_back
typedef vector<int> vi;
typedef vector<ll> vll;
typedef vector<ii> vii;
typedef vector<iii> viii;
#ifndef DEBUG
#define cerr if (0) cerr
#endif
const int INF = 1000000005;
const ll LINF = 1000000000000000005ll;
const int MAXN = 500005;
int n;
int a[MAXN];
int q;
vii qry[MAXN];
vi ev[MAXN];
ll ans[MAXN];
ll mx[MAXN];
void updmx(int s, int e, ll x) {
REP (i, s, e + 1) {
mxto(mx[i], x);
}
}
ll qmx(int s, int e) {
ll res = 0;
REP (i, s, e + 1) {
mxto(res, a[i] + mx[i]);
}
return res;
}
int main() {
#ifndef DEBUG
ios::sync_with_stdio(0), cin.tie(0);
#endif
cin >> n;
REP (i, 1, n + 1) {
cin >> a[i];
}
REP (j, 1, n + 1) {
mx[j] = -INF;
}
vi stk;
REP (j, 1, n + 1) {
while (!stk.empty() && a[stk.back()] < a[j]) {
ev[stk.back()].pb(j);
stk.pop_back();
}
if (!stk.empty()) {
ev[stk.back()].pb(j);
}
stk.pb(j);
}
stk.clear();
RREP (j, n, 1) {
while (!stk.empty() && a[stk.back()] < a[j]) {
ev[j].pb(stk.back());
stk.pop_back();
}
if (!stk.empty()) {
ev[j].pb(stk.back());
}
stk.pb(j);
}
cin >> q;
REP (i, 1, q + 1) {
int l, r; cin >> l >> r;
qry[l].pb({r, i});
}
RREP (l, n, 1) {
for (int r : ev[l]) {
// c - r = r - l
// c = 2 * r - l
if (2 * r - l <= n) {
updmx(2 * r - l, n, a[l] + a[r]);
}
}
for (auto [r, i] : qry[l]) {
ans[i] = qmx(l, r);
}
}
REP (i, 1, q + 1) {
cout << ans[i] << '\n';
}
return 0;
}
