제출 #832909

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
832909		ikaurov	휴가 (IOI14_holiday)	C++17	47 / 100	131 ms	65536 KiB

holiday

#include"holiday.h"
#include <bits/stdc++.h>
using namespace std;
#define sz(x) (int)(x).size()
#define all(arr) (arr).begin(), (arr).end()
#define ll long long
#define ld long double
#define pb push_back
#define fi first
#define se second

const int N = 1e5 + 20;

unsigned ll getval(ll sum, int cnt){
  return (sum << 17) + cnt;
}

ll getsum(unsigned ll val){
  return val >> 17;
}

int getcnt(ll val){
  return val & ((1 << 17) - 1);
}

struct Node{
  unsigned ll val;
  Node* l;
  Node* r;
  Node(){
    val = 0, l = r = nullptr;
  };
  Node(ll sum, int cnt){
    val = getval(sum, cnt), l = r = nullptr;
  }
  Node(Node* l_, Node* r_){
    l = l_, r = r_, val = getval(getsum(l -> val) + getsum(r -> val), getcnt(l -> val) + getcnt(r -> val));
  };
};

Node* root[N];

Node* build(int tl, int tr){
  if (tl == tr) return new Node();
  int tm = (tl + tr) / 2;
  return new Node(build(tl, tm), build(tm + 1, tr));
}

Node* modify(Node* v, int tl, int tr, int pos, int val){
  if (tl == tr) return new Node(getsum(v -> val) + val, getcnt(v -> val) + 1);
  int tm = (tl + tr) / 2;
  if (pos <= tm) return new Node(modify(v -> l, tl, tm, pos, val), v -> r);
  else return new Node(v -> l, modify(v -> r, tm + 1, tr, pos, val));
}

ll query(Node* v, int tl, int tr, int& need){
  if (getcnt(v -> val) <= need){
    need -= getcnt(v -> val);
    return getsum(v -> val);
  }
  if (tl == tr){
    ll ret = need * (getsum(v -> val) / getcnt(v -> val));
    need = 0;
    return ret;
  }
  int tm = (tl + tr) / 2;
  ll ret = query(v -> r, tm + 1, tr, need);
  if (need) ret += query(v -> l, tl, tm, need);
  return ret;
}

int m, weight;
vector<ll> dp;

ll calc(int d, int pref){
  d -= pref * weight;
  return d > 0? query(root[pref], 0, m - 1, d) : 0;
}

void rec(int l, int r, int optl, int optr){
  if (l > r) return;
  int mid = (l + r) / 2;
  int opt = optl;
  ll optval = 0;
  for (int i = optl; i <= optr; i++){
    ll cur = calc(mid, i);
    if (cur > optval) optval = cur, opt = i;
  }
  dp[mid] = optval;
  rec(l, mid - 1, optl, opt);
  rec(mid + 1, r, opt, optr);
}

vector<ll> solve(vector<int> a, int maxd, int w){
  int n = sz(a);
  if (!n){
    return vector<ll>(maxd + 1);
  }
  vector<int> vals = a;
  sort(all(vals));
  vals.erase(unique(all(vals)), vals.end());
  m = sz(vals), weight = w;
  if (w == 1){
    root[0] = build(0, m - 1);
    for (int i = 0; i < n; i++){
      if (i) root[i] = root[i - 1];
      root[i] = modify(root[i], 0, m - 1, lower_bound(all(vals), a[i]) - vals.begin(), a[i]);
    }
  }
  dp.resize(maxd + 1);
  rec(0, maxd, 0, n - 1);
  return dp;
}

long long int findMaxAttraction(int n, int start, int d, int a[]) {
  if (!d) return 0;
  vector<int> lft, rgt;
  for (int i = 0; i < start; i++) lft.pb(a[i]);
  for (int i = start + 1; i < n; i++) rgt.pb(a[i]);
  reverse(all(lft));
  auto left_noret = solve(lft, d, 1), left_ret = solve(lft, d, 2);
  auto right_noret = solve(rgt, d, 1), right_ret = solve(rgt, d, 2);

  ll ans = 0;
  for (int takeleft = 1; takeleft <= d; takeleft++){
    ans = max(ans, left_noret[takeleft - 1]);
  }
  for (int takeright = 1; takeright <= d; takeright++){
    ans = max(ans, right_noret[takeright - 1]);
  }
  for (int dleft = 1; dleft < d; dleft++){
    int dright = d - dleft;
    if (dleft >= 2) ans = max(ans, left_ret[dleft - 2] + right_noret[dright - 1]);
    if (dright >= 2) ans = max(ans, left_noret[dleft - 1] + right_ret[dright - 2]);
  }

  ll ret = ans;
  d--;

  ans = 0;
  for (int takeleft = 1; takeleft <= d; takeleft++){
    ans = max(ans, left_noret[takeleft - 1]);
  }
  for (int takeright = 1; takeright <= d; takeright++){
    ans = max(ans, right_noret[takeright - 1]);
  }
  for (int dleft = 1; dleft < d; dleft++){
    int dright = d - dleft;
    if (dleft >= 2) ans = max(ans, left_ret[dleft - 2] + right_noret[dright - 1]);
    if (dright >= 2) ans = max(ans, left_noret[dleft - 1] + right_ret[dright - 2]);
  }

  return max(ret, ans + a[start]);
}

• Subtask 1: 7 / 7
• Subtask 2: 23 / 23
• Subtask 3: 17 / 17
• Subtask 4: 0 / 53