Submission #83148

#TimeUsernameProblemLanguageResultExecution timeMemory
83148MrTEK수열 (APIO14_sequence)C++14
0 / 100
3 ms876 KiB
#include <bits/stdc++.h> using namespace std; typedef long long int ll; typedef pair<int,int> ii; const int N = 1e3 + 5; const int M = 205; int a[N],n,k; ll pre[N],dp[N][2]; ll get(int l,int r) { return pre[r] - pre[l - 1]; } void f(int l,int r,int optl,int optr) { if (l > r || optl > optr) return; int mid = (l + r) / 2; if (optl == optr) dp[mid][0] = optl; else { for (int i = min(mid + 1,optl) ; i <= optr ; i++) dp[mid][0] = max(dp[mid][0],dp[i][1] + get(mid,i - 1) * get(i,n)); } f(l,mid - 1,optl,dp[mid][0]); f(mid + 1,r,dp[mid][0],optr); } int main() { ios_base::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL); cin >> n >> k; for (int i = 1 ; i <= n ; i++) { cin >> a[i]; pre[i] = pre[i - 1] + a[i]; } for (int i = 0 ; i <= k ; i++) { for (int j = 1 ; j <= n ; j++) { dp[j][1] = dp[j][0]; dp[j][0] = 0; } f(1,n,1,n); } cout << dp[1][0] << "\n"; }
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