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답안 #830658

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
830658 2023-08-19T08:57:38 Z green_gold_dog Sandcastle 2 (JOI22_ho_t5) C++17
71 / 100
 5000 ms 349824 KB 
//#pragma GCC optimize("Ofast")
//#pragma GCC target("avx,avx2,sse,sse2,sse3,ssse3,sse4,abm,popcnt,mmx")
#include <bits/stdc++.h>

using namespace std;

typedef int ll;
typedef double db;
typedef long double ldb;
typedef complex<double> cd;

constexpr ll INF64 = 9'000'000'000'000'000'000, INF32 = 2'000'000'000, MOD = 1'000'000'007;
constexpr db PI = acos(-1);
constexpr bool IS_FILE = false, IS_TEST_CASES = false;

random_device rd;
mt19937 rnd32(rd());
mt19937_64 rnd64(rd());

template<typename T>
bool assign_max(T& a, T b) {
        if (b > a) {
                a = b;
                return true;
        }
        return false;
}

template<typename T>
bool assign_min(T& a, T b) {
        if (b < a) {
                a = b;
                return true;
        }
        return false;
}

template<typename T>
T square(T a) {
        return a * a;
}

template<>
struct std::hash<pair<ll, ll>> {
        ll operator() (pair<ll, ll> p) const {
                return ((__int128)p.first * MOD + p.second) % INF64;
        }
};

ll get(vector<vector<vector<vector<vector<vector<ll>>>>>>& dp2, vector<vector<vector<vector<vector<vector<ll>>>>>>& pref, ll x1, ll y1, ll x2, ll y2, ll xg) {
        ll bu = min(2, xg - x1), bd = min(2, x2 - xg);
        if (y2 - y1 > 4) {
                return pref[xg][y2 - 2][bu][2][bd][2] - pref[xg][y1 + 2][bu][2][bd][2] + dp2[xg][y1][bu][0][bd][2] + dp2[xg][y1 + 1][bu][1][bd][2] + dp2[xg][y2 - 1][bu][2][bd][0] + dp2[xg][y2 - 2][bu][2][bd][1];
        }
        if (y2 - y1 == 4) {
                return dp2[xg][y1][bu][0][bd][2] + dp2[xg][y1 + 1][bu][1][bd][2] + dp2[xg][y2 - 1][bu][2][bd][0] + dp2[xg][y2 - 2][bu][2][bd][1];
        }
        if (y2 - y1 == 3) {
                return dp2[xg][y1][bu][0][bd][2] + dp2[xg][y1 + 1][bu][1][bd][1] + dp2[xg][y2 - 1][bu][2][bd][0];
        }
        if (y2 - y1 == 2) {
                return dp2[xg][y1][bu][0][bd][1] + dp2[xg][y2 - 1][bu][1][bd][0];
        }
        if (y2 - y1 == 1) {
                return dp2[xg][y1][bu][0][bd][0];
        }
        return 0;
}

void solve() {
        ll n, m;
        cin >> n >> m;
        bool b = false;
        if (n < m) {
                swap(n, m);
                b = true;
        }
        vector<vector<ll>> arr(n, vector<ll>(m));
        if (!b) {
                for (ll i = 0; i < n; i++) {
                        for (ll j = 0; j < m; j++) {
                                cin >> arr[i][j];
                        }
                }
        } else {
                for (ll i = 0; i < m; i++) {
                        for (ll j = 0; j < n; j++) {
                                cin >> arr[j][i];
                        }
                }
        }
        vector<vector<vector<vector<vector<vector<ll>>>>>> dp1(n, vector(m, vector(2, vector(2, vector(2, vector<ll>(2, -1))))));
        vector<vector<vector<vector<vector<vector<ll>>>>>> dp2(n, vector(m, vector(3, vector(3, vector(3, vector<ll>(3, 0))))));
        vector<vector<vector<vector<vector<vector<ll>>>>>> pref(n, vector(m + 1, vector(3, vector(3, vector(3, vector<ll>(3, 0))))));
        vector<vector<vector<vector<vector<ll>>>>> so(n, vector(m, vector(m + 1, vector(3, vector<ll>(3, 0)))));
        for (ll i = 0; i < n; i++) {
                for (ll j = 0; j < m; j++) {
                        ll mi = -1;
                        for (ll bu = 0; bu <= 1; bu++) {
                                if (bu && i == 0) {
                                        continue;
                                }
                                ll fir = mi;
                                if (bu && arr[i][j] > arr[i - 1][j]) {
                                        assign_max(mi, arr[i - 1][j]);
                                }
                                for (ll bl = 0; bl <= 1; bl++) {
                                        if (bl && j == 0) {
                                                continue;
                                        }
                                        ll fir = mi;
                                        if (bl && arr[i][j] > arr[i][j - 1]) {
                                                assign_max(mi, arr[i][j - 1]);
                                        }
                                        for (ll bd = 0; bd <= 1; bd++) {
                                                if (bd && i == n - 1) {
                                                        continue;
                                                }
                                                ll fir = mi;
                                                if (bd && arr[i][j] > arr[i + 1][j]) {
                                                        assign_max(mi, arr[i + 1][j]);
                                                }
                                                for (ll br = 0; br <= 1; br++) {
                                                        if (br && j == m - 1) {
                                                                continue;
                                                        }
                                                        ll fir = mi;
                                                        if (br && arr[i][j] > arr[i][j + 1]) {
                                                                assign_max(mi, arr[i][j + 1]);
                                                        }
                                                        dp1[i][j][bu][bl][bd][br] = mi;
                                                        mi = fir;
                                                }
                                                mi = fir;
                                        }
                                        mi = fir;
                                }
                                mi = fir;
                        }
                }
        }
        for (ll i = 0; i < n; i++) {
                for (ll j = 0; j < m; j++) {
                        for (ll bu = 0; bu <= 2; bu++) {
                                if (i - bu < 0) {
                                        continue;
                                }
                                for (ll bl = 0; bl <= 2; bl++) {
                                        if (j - bl < 0) {
                                                continue;
                                        }
                                        for (ll bd = 0; bd <= 2; bd++) {
                                                if (i + bd >= n) {
                                                        continue;
                                                }
                                                for (ll br = 0; br <= 2; br++) {
                                                        if (j + br >= m) {
                                                                continue;
                                                        }
                                                        if (bu) {
                                                                dp2[i][j][bu][bl][bd][br] += arr[i][j] == dp1[i - 1][j][bu - 1][min(bl, 1)][1][min(br, 1)];
                                                        }
                                                        if (bd) {
                                                                dp2[i][j][bu][bl][bd][br] += arr[i][j] == dp1[i + 1][j][1][min(bl, 1)][bd - 1][min(br, 1)];
                                                        }
                                                        if (bl) {
                                                                dp2[i][j][bu][bl][bd][br] += arr[i][j] == dp1[i][j - 1][min(bu, 1)][bl - 1][min(bd, 1)][1];
                                                        }
                                                        if (br) {
                                                                dp2[i][j][bu][bl][bd][br] += arr[i][j] == dp1[i][j + 1][min(bu, 1)][1][min(bd, 1)][br - 1];
                                                        }
                                                        dp2[i][j][bu][bl][bd][br] ^= 1;
                                                        pref[i][j + 1][bu][bl][bd][br] = pref[i][j][bu][bl][bd][br] + dp2[i][j][bu][bl][bd][br];
                                                }
                                        }
                                }
                        }
                }
        }
        for (ll i = 0; i < n; i++) {
                for (ll j = 0; j < m; j++) {
                        for (ll k = j + 1; k <= m; k++) {
                                for (ll bu = 0; bu <= 2; bu++) {
                                        for (ll bd = 0; bd <= 2; bd++) {
                                                so[i][j][k][bu][bd] = get(dp2, pref, i - bu, j, i + bd, k, i);
                                        }
                                }
                        }
                }
        }
        ll ans = 0;
        for (ll i = 0; i < n; i++) {
                for (ll j = 0; j < m; j++) {
                        for (ll k = j + 1; k <= m; k++) {
                                ll na = 0;
                                for (ll aj = 0; aj + i < n; aj++) {
                                        ll ns = 0, sna = na;
                                        if (aj >= 2) {
                                                na += ns += so[i + aj - 2][j][k][min(2, aj - 2)][2];
                                                if (na > 1) {
                                                        break;
                                                }
                                        }
                                        for (ll naj = max(0, aj - 1); naj <= aj; naj++) {
                                                ns += so[i + naj][j][k][min(2, naj)][aj - naj];
                                                if (sna + ns > 1) {
                                                        break;
                                                }
                                        }
                                        if (ns + sna == 1) {
                                                ans++;
                                        }
                                }
                        }
                }
        }
        cout << ans << '\n';
}

int main() {
        if (IS_FILE) {
                freopen("", "r", stdin);
                freopen("", "w", stdout);
        }
        ios_base::sync_with_stdio(false);
        cin.tie(0);
        cout.tie(0);
        ll t = 1;
        if (IS_TEST_CASES) {
                cin >> t;
        }
        for (ll i = 0; i < t; i++) {
                solve();
        }
}

Compilation message

Main.cpp:12:22: warning: overflow in conversion from 'long int' to 'll' {aka 'int'} changes value from '9000000000000000000' to '-494665728' [-Woverflow]
   12 | constexpr ll INF64 = 9'000'000'000'000'000'000, INF32 = 2'000'000'000, MOD = 1'000'000'007;
      |                      ^~~~~~~~~~~~~~~~~~~~~~~~~
Main.cpp: In function 'int main()':
Main.cpp:222:24: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)' declared with attribute 'warn_unused_result' [-Wunused-result]
  222 |                 freopen("", "r", stdin);
      |                 ~~~~~~~^~~~~~~~~~~~~~~~
Main.cpp:223:24: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)' declared with attribute 'warn_unused_result' [-Wunused-result]
  223 |                 freopen("", "w", stdout);
      |                 ~~~~~~~^~~~~~~~~~~~~~~~~

Subtask #1
0 / 9.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 340 KB Output is correct
2 Execution timed out 5059 ms 349764 KB Time limit exceeded
3 Halted 0 ms 0 KB -

Subtask #2
10.0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 852 KB Output is correct
2 Correct 1 ms 980 KB Output is correct
3 Correct 1 ms 980 KB Output is correct
4 Correct 1 ms 980 KB Output is correct
5 Correct 1 ms 980 KB Output is correct
6 Correct 1 ms 852 KB Output is correct

Subtask #3
5.0 / 5.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 852 KB Output is correct
2 Correct 1 ms 980 KB Output is correct
3 Correct 1 ms 980 KB Output is correct
4 Correct 1 ms 980 KB Output is correct
5 Correct 1 ms 980 KB Output is correct
6 Correct 1 ms 852 KB Output is correct
7 Correct 20 ms 10708 KB Output is correct
8 Correct 11 ms 10820 KB Output is correct
9 Correct 22 ms 17684 KB Output is correct
10 Correct 28 ms 16468 KB Output is correct
11 Correct 17 ms 9536 KB Output is correct
12 Correct 20 ms 9532 KB Output is correct
13 Correct 29 ms 18260 KB Output is correct
14 Correct 15 ms 11860 KB Output is correct
15 Correct 22 ms 16468 KB Output is correct
16 Correct 21 ms 16412 KB Output is correct

Subtask #4
56.0 / 56.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 852 KB Output is correct
2 Correct 1 ms 980 KB Output is correct
3 Correct 1 ms 980 KB Output is correct
4 Correct 1 ms 980 KB Output is correct
5 Correct 1 ms 980 KB Output is correct
6 Correct 1 ms 852 KB Output is correct
7 Correct 20 ms 10708 KB Output is correct
8 Correct 11 ms 10820 KB Output is correct
9 Correct 22 ms 17684 KB Output is correct
10 Correct 28 ms 16468 KB Output is correct
11 Correct 17 ms 9536 KB Output is correct
12 Correct 20 ms 9532 KB Output is correct
13 Correct 29 ms 18260 KB Output is correct
14 Correct 15 ms 11860 KB Output is correct
15 Correct 22 ms 16468 KB Output is correct
16 Correct 21 ms 16412 KB Output is correct
17 Correct 248 ms 49248 KB Output is correct
18 Correct 140 ms 103756 KB Output is correct
19 Correct 80 ms 50896 KB Output is correct
20 Correct 962 ms 142144 KB Output is correct
21 Correct 196 ms 146236 KB Output is correct
22 Correct 194 ms 146276 KB Output is correct
23 Correct 189 ms 141440 KB Output is correct
24 Correct 153 ms 107272 KB Output is correct
25 Correct 175 ms 132808 KB Output is correct
26 Correct 182 ms 138632 KB Output is correct
27 Correct 181 ms 132812 KB Output is correct
28 Correct 180 ms 138608 KB Output is correct

Subtask #5
0 / 20.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 852 KB Output is correct
2 Correct 1 ms 980 KB Output is correct
3 Correct 1 ms 980 KB Output is correct
4 Correct 1 ms 980 KB Output is correct
5 Correct 1 ms 980 KB Output is correct
6 Correct 1 ms 852 KB Output is correct
7 Correct 20 ms 10708 KB Output is correct
8 Correct 11 ms 10820 KB Output is correct
9 Correct 22 ms 17684 KB Output is correct
10 Correct 28 ms 16468 KB Output is correct
11 Correct 17 ms 9536 KB Output is correct
12 Correct 20 ms 9532 KB Output is correct
13 Correct 29 ms 18260 KB Output is correct
14 Correct 15 ms 11860 KB Output is correct
15 Correct 22 ms 16468 KB Output is correct
16 Correct 21 ms 16412 KB Output is correct
17 Correct 248 ms 49248 KB Output is correct
18 Correct 140 ms 103756 KB Output is correct
19 Correct 80 ms 50896 KB Output is correct
20 Correct 962 ms 142144 KB Output is correct
21 Correct 196 ms 146236 KB Output is correct
22 Correct 194 ms 146276 KB Output is correct
23 Correct 189 ms 141440 KB Output is correct
24 Correct 153 ms 107272 KB Output is correct
25 Correct 175 ms 132808 KB Output is correct
26 Correct 182 ms 138632 KB Output is correct
27 Correct 181 ms 132812 KB Output is correct
28 Correct 180 ms 138608 KB Output is correct
29 Execution timed out 5049 ms 349824 KB Time limit exceeded
30 Halted 0 ms 0 KB -