이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#define inf INT_MAX
#define longlonginf LONG_LONG_MAX
#define mod 998244353
#define MAXN 5000
#define pll pair<ll,ll>
#define ll long long
#define deb(x) cerr<<"[ "<<#x<<" = "<<x<<" ]";
#define yes() cout<<"YES\n";
#define no() cout<<"NO\n";
using namespace std;
ll n,m,k,q,x;
ll h;
ll ans = 0;
string subtask;
ll sub3 = 0;
void solve(){
cin>>n>>k;
ll dp[2][MAXN+5];
k = min(k,(ll)5000);
ll a[n];
for(int i = 0 ; i < n ; i++){
cin>>a[i];
}
if( k == 0 ){
sort(a,a+n);
x = 0;
ans = longlonginf;
for(int i = 0 ; i < n ; i++){
x += a[i];
}
ll pref = 0;
for(int i = 0 ; i < n ; i++){
pref += a[i];
x -= a[i];
ans = min((i+1)*a[i] - pref + x - (n-(i+1))*a[i],ans);
}
cout<<ans<<"\n";
return;
}
for(int i = 0 ; i <= MAXN ; i++){
dp[0][i] = abs(a[0]-i);
}
for(int i = 1 ; i < n ; i++){
multiset<ll> s;
for(int j = 0 ; j < k ; j++){
s.insert(dp[0][j]);
}
for(int j = 0 ; j <= MAXN ; j++){
if( j + k <= MAXN ) s.insert(dp[0][j+k]);
if( j - k > 0 ) s.erase(s.lower_bound(dp[0][j-k-1]));
dp[1][j] = abs(a[i]-j) + *s.begin();
//cout<<i<<" "<<j<<" : "<<dp[i][j]<<"\n";
}
for(int j = 0 ; j <= MAXN ; j++){
dp[0][j] = dp[1][j];
}
}
ans = longlonginf;
for(int i = 0 ; i <= MAXN ; i++){
ans = min(ans,dp[0][i]);
}
cout<<ans<<"\n";
}
int main(){
ios_base::sync_with_stdio(false);
cin.tie(0);
cout.tie(0);
int T = 1;
//cin>>T;
for(int i = 0 ; i < T ; i++){
//cout<<"Case #"<<i+1<<": ";
solve();
}
return 0;
}
/*
not i but x
logical operator
wrong example/proof
thoroughly
wrong variables
thinking it wrong
bruh just try some test case
capitals ;-;
wrong data structure lol
count memory usement
corner case
oversized array
orders
statements
size initializer
while con
map -> array
wrong digits??
swapped variables??
check if theres any variabled
that got declared twice
find some pattern
name collision
constraints??!
mod !!
resets
*/
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