Submission #825514

#	Time	Username	Problem	Language	Result	Execution time	Memory
825514		NK_	Building Bridges (CEOI17_building)	C++17	0 / 100	965 ms	27888 KiB

building

// Success consists of going from failure to failure without loss of enthusiasm
#include <bits/stdc++.h>

using namespace std;

#define nl '\n'
#define pb push_back 
#define mp make_pair
#define f first
#define s second
#define sz(x) int(x.size())

template<class T> using V = vector<T>;
using vi = V<int>;
using pi = pair<int, int>;
using ll = long long;
using vl = V<ll>;

const ll INFL = ll(1e16) + 1008;
const int nax = 1e6 + 6;
const int SQ = 1e3 + 1;
vi oc[nax];

int main() {
	cin.tie(0)->sync_with_stdio(0);
	
	int N; cin >> N;
	vi A(N); for(auto& x : A) cin >> x;
	vi W(N); for(auto& x : W) cin >> x;

	vl P = {0}; for(auto& x : W) P.pb(P.back() + x);

	auto query = [&](int l, int r) {
		if (l > r) return 0LL;
		return P[r + 1] - P[l];
	};

	auto sq = [&](int x) { return x * 1LL * x; };

	vl dp(N, INFL); dp[0] = 0;

	oc[A[0]].pb(0);
	for(int i = 1; i < N; i++) {
		int x = A[i];
		for(int d = max(-SQ, -x); d <= min(SQ, nax-1-x); d++) {
			int y = x + d; 
			if (sz(oc[y]) == 0) continue;
			int j = oc[y].back(); ll cost = sq(x - y) + query(j + 1, i - 1); 
			// cout << i << " " << j << " => " << cost << endl;
			dp[i] = min(dp[i], dp[j] + cost);
		}

		oc[x].pb(i);
	}

	cout << dp.back() << nl;

    return 0;
}			

• Subtask 1: 0 / 30
• Subtask 2: 0 / 30
• Subtask 3: 0 / 40