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// teddybear's code
// the one who loves NBP
// noe the second
// goal: 0 / 8
// get medal in APIO (like TKN)
//#pragma GCC optimize("O3,unroll-loops")
//#pragma GCC target("avx2,bmi,bmi2,popcnt,lzcnt")
// prob:
#include <bits/stdc++.h>
using namespace std;
#pragma GCC optimize("Ofast")
#pragma GCC target("avx,avx2,fma")
#define FOR(i,n) for (int i = 0; i<n; i++)
using ll = long long;
using ull = unsigned long long;
ll n,m,t;
ll cnt = 0;
const int maxn = 1e5;
const ll mod = 1e9 + 7;
#define Y "YES"
#define N "NO"
ll a[2 * maxn + 5];
ll b[2 * maxn + 5];
bool visited[1005][1005];
int dist[1005][1005];
int w,h;
int fx[4] = {-1, 1, 0, 0};
int fy[4] = {0, 0, -1, 1};
queue <pair<int,int>> q;
ll dis[2 * maxn + 5];
pair<ll,ll> p[2 * maxn + 5];
ll dp[2 * maxn + 5];
vector <ll> bactrac(ll l, ll r)
{
ll len = r - l + 1;
vector <ll> ans;
for (ll i = 0; i<(1<<len); i++)
{
ll res = 0;
for (ll j = 0; j<len; j++)
{
if (i & (1 << j))
{
res += b[l + j];
}
}
ans.push_back(res);
}
return ans;
}
void sub1()
{
vector <ll> le = bactrac(1,m/2);
vector <ll> ri = bactrac(m/2+1,m);
sort(le.begin(), le.end());
sort(ri.begin(), ri.end());
for (ll j : le)
{
ll curr = lower_bound(ri.begin(), ri.end(), a[1] - j) - ri.begin();
//cout << "! " << j << ' ' << ri[curr] << '\n';
if (curr < ri.size() && (j + ri[curr]) == a[1])
{
cout << "YES";
return;
}
}
cout << "NO";
}
void solve()
{
cin >> n >> m;
for (int i = 1; i<=n; i++)
{
cin >> a[i];
}
for (int i = 1; i<=m; i++)
{
cin >> b[i];
}
if (n == 1)
{
sub1();
}
}
void init()
{
int te = 1; //cin >> te;
while (te--)
{
solve();
}
}
void preprocess()
{
}
int main()
{
ios_base::sync_with_stdio(false);
cin.tie(NULL);
//cin.tie(0); cout.tie(0);
//freopen(".inp", "r", stdin);
//freopen(".out", "w", stdout);
init();
preprocess();
//solve();
return 0;
}
컴파일 시 표준 에러 (stderr) 메시지
bank.cpp: In function 'void sub1()':
bank.cpp:67:12: warning: comparison of integer expressions of different signedness: 'll' {aka 'long long int'} and 'std::vector<long long int>::size_type' {aka 'long unsigned int'} [-Wsign-compare]
67 | if (curr < ri.size() && (j + ri[curr]) == a[1])
| ~~~~~^~~~~~~~~~~
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