이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
// teddybear's code
// the one who loves NBP
// noe the second
// goal: 0 / 8
// get medal in APIO (like TKN)
//#pragma GCC optimize("O3,unroll-loops")
//#pragma GCC target("avx2,bmi,bmi2,popcnt,lzcnt")
// prob:
#include <bits/stdc++.h>
using namespace std;
#pragma GCC optimize("Ofast")
#pragma GCC target("avx,avx2,fma")
#define FOR(i,n) for (int i = 0; i<n; i++)
using ll = long long;
using ull = unsigned long long;
ll n,m,t;
ll cnt = 0;
const int maxn = 1e5;
const ll mod = 1e9 + 7;
#define Y "YES"
#define N "NO"
ll a[2 * maxn + 5];
bool visited[1005][1005];
int dist[1005][1005];
int w,h;
int fx[4] = {-1, 1, 0, 0};
int fy[4] = {0, 0, -1, 1};
queue <pair<int,int>> q;
ll dis[2 * maxn + 5];
pair<ll,ll> p[2 * maxn + 5];
void solve()
{
cin >> n;
for (int i = 1; i<=n; i++)
{
cin >> p[i].first >> p[i].second;
}
sort(p+1,p+n+1);
ll mx = 0;
for (int i = 1; i<=n; i++)
{
ll up = -1, down = 1e16;
ll tmp = 0, sum = 0;
for (int j = i; j<=n; j++)
{
sum += p[j].second;
up = max(up, p[j].first);
down = min(down, p[j].first);
tmp = max(tmp, sum + down - up);
}
mx = max(mx, tmp);
}
cout << mx;
}
void init()
{
int te = 1; //cin >> te;
while (te--)
{
solve();
}
}
void preprocess()
{
}
int main()
{
ios_base::sync_with_stdio(false);
cin.tie(NULL);
//cin.tie(0); cout.tie(0);
//freopen(".inp", "r", stdin);
//freopen(".out", "w", stdout);
init();
preprocess();
//solve();
return 0;
}
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