제출 #822982

#제출 시각아이디문제언어결과실행 시간메모리
822982vjudge1Rectangles (IOI19_rect)C++17
10 / 100
3 ms612 KiB
#include<bits/stdc++.h> #include "rect.h" using namespace std; using ll = long long; // O(nlogn) set<pair<int, int>> get_segments(vector<int> &a) { vector<pair<int, int>> b; set<pair<int, int>> res; int n = (int)a.size(); for(int i = 0; i < n; i++) { b.push_back({a[i], i}); } sort(b.rbegin(), b.rend()); set<int> st; for(auto [x, pos] : b) { st.insert(pos); auto it = st.lower_bound(pos); if(it != st.begin()) { auto lb = it; lb--; if(*it - *lb > 1) res.insert({*lb + 1, *it - 1}); } if(it != (--st.end())) { auto rb = it; rb++; if(*rb - *it > 1) res.insert({*it + 1, *rb - 1}); } } return res; } template<typename T> void intersect(set<T> &st, set<T> st1) { set<T> st2; for(auto x : st1) { if(st.count(x)) st2.insert(x); } st = st2; } ll count_rectangles(vector<vector<int>> a) { int n = (int)a.size(), m = (int)a[0].size(); if(n < 3 || m < 3) return 0; ll res = 0; for(int r1 = 1; r1 < n - 1; r1++) { set<pair<int, int>> seg; vector<int> mx(m); for(int r2 = r1; r2 < n - 1; r2++) { for(int i = 0; i < m; i++) mx[i] = max(mx[i], a[r2][i]); vector<int> pre(m); for(int i = 0; i < m; i++) { pre[i] = (mx[i] < min(a[r1 - 1][i], a[r2 + 1][i])); if(i) pre[i] += pre[i - 1]; } if(r1 == r2) seg = get_segments(a[r2]); else intersect(seg, get_segments(a[r2])); for(auto [l, r] : seg) { int x = pre[r] - (l ? pre[l - 1] : 0); if(x == r - l + 1) res++; } } } return res; }
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