Submission #816002

#	Time	Username	Problem	Language	Result	Execution time	Memory
816002		Magikarp4000	Art Class (IOI13_artclass)	C++17	0 / 100	5093 ms	11148 KiB

artclass

#include "artclass.h"
#include <bits/stdc++.h>
using namespace std;
#define OPTM ios_base::sync_with_stdio(0); cin.tie(0);
#define INF int(1e9+7)
#define ln '\n' 
#define ll long long
#define ull unsigned long long
#define ui unsigned int
#define us unsigned short
#define FOR(i,s,n) for (int i = s; i < n; i++)
#define FORR(i,n,s) for (int i = n; i > s; i--)
#define FORX(u, arr) for (auto u : arr)
#define PB push_back
#define F first
#define S second
#define PII pair<int, int>
#define PLL pair<ll, ll>
#define UM unordered_map
#define US unordered_set
#define PQ priority_queue
#define ALL(v) v.begin(), v.end()
const ll LLINF = 1e18+1;

const int dx[] = {0,0,1,-1};
const int dy[] = {1,-1,0,0};
const int VAR = 30;
const int EPS = 10;
const int EPS1 = 10;

struct Coord {
    PII tp,ri,bt,le;
};

const int MAXN = 5e2+5;
int h, w, r[MAXN][MAXN], g[MAXN][MAXN], b[MAXN][MAXN], z[MAXN][MAXN];
vector<Coord> v;
vector<int> cnts;

bool same(int x1, int y1, int x2, int y2) {
    int diff = abs(r[y1][x1]-r[y2][x2])+abs(g[y1][x1]-g[y2][x2])+abs(b[y1][x1]-b[y2][x2]);
    return diff <= VAR;
}

void bfs(int sx, int sy, int idx) {
    queue<PII> q;
    q.push({sx,sy});
    while (!q.empty()) {
        int x = q.front().F, y = q.front().S;
        q.pop();
        z[y][x] = idx;
        FOR(i,0,4) {
            int nx = x+dx[i], ny = y+dy[i];
            if (nx < 0 || nx >= w || ny < 0 || ny >= h) continue;
            if (z[ny][nx]) continue;
            if (same(x,y,nx,ny)) {
                z[ny][nx] = idx;
                q.push({nx,ny});
            }
        }
    }
    Coord cur = {{-1,-1},{-1,-1},{-1,-1},{-1,-1}};
    FOR(i,0,h) {
        FOR(j,0,w) {
            if (z[i][j]) {
                cur.tp = {j,i};
                break;
            }
        }
    }
    FORR(j,w-1,-1) {
        FOR(i,0,h) {
            if (z[i][j]) {
                cur.ri = {j,i};
                break;
            }
        }
    }
    FORR(i,h-1,-1) {
        FORR(j,w-1,-1) {
            if (z[i][j]) {
                cur.bt = {j,i};
                break;
            }
        }
    }
    FOR(j,0,w) {
        FORR(i,h,-1) {
            if (z[i][j]) {
                cur.le = {j,i};
                break;
            }
        }
    }
    v.PB(cur);
    int cnt = 0;
    FOR(i,0,h) FOR(j,0,w) cnt += z[i][j] > 0;
    cnts.PB(cnt);
}

int style(int H, int W, int R[500][500], int G[500][500], int B[500][500]) {
    h = H, w = W;
    FOR(i,0,h) FOR(j,0,w) r[i][j] = R[i][j], g[i][j] = G[i][j], b[i][j] = B[i][j];
    int idx = 1;
    FOR(i,0,h) {
        FOR(j,0,w) {
            if (z[i][j]) continue;
            // if (r[i][j]+g[i][j]+b[i][j] <= VAR) continue;
            bfs(j,i,idx++);
        }
    }
    int vn = v.size(), num = 0;
    FORX(u,v) {
        int val = (u.tp.S-u.le.S)*(u.ri.F-u.bt.F);
        int val1 = (u.ri.S-u.bt.S)*(u.tp.F-u.le.F);
        if (abs(val-val1) <= EPS) num++;
    }
    if (num >= 5) return 1;
    FOR(k,0,vn) {
        Coord u = v[k];
        if (abs(u.ri.F-u.tp.F) <= EPS1
            && abs(u.ri.S-u.bt.S) <= EPS1
            && abs(u.bt.F-u.le.F) <= EPS1
            && abs(u.tp.S-u.le.S) <= EPS1
        ) {
            int bad = 0;
            FOR(i,u.tp.S,u.bt.S+1) {
                FOR(j,u.le.F,u.ri.F+1) bad += z[i][j] != k+1;
            }
            if ((u.tp.S-u.bt.S)*(u.ri.F-u.le.F) <= h*w/10) continue;
            if (bad <= 5) return 4; 
        }
    }
    int gre = 0;
    FOR(i,0,h) FOR(j,0,w) gre += g[i][j];
    if (gre >= h*w*255/3) return 2;
    // FORX(u,cnts) if (u >= h*w/4) return 4;
    return 3;
}

• Subtask 1: 0 / 100