제출 #814764

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
814764		gesgha	열쇠 (IOI21_keys)	C++17	37 / 100	3049 ms	40500 KiB

keys

#include <bits/stdc++.h>
 
#define fr(i, a, b) for(int i = a; i <= b; i++)
#define rf(i, a, b) for(int i = a; i >= b; i--)
#define fe(x, y) for (auto& x : y)
 
#define fi first
#define se second
#define pb push_back
 
#define all(x) x.begin(), x.end()
#define pw(x) (1LL << (x))
#define sz(x) (int)x.size()
 
using namespace std;
 
#include <ext/pb_ds/assoc_container.hpp>
using namespace __gnu_pbds;
#define fbo find_by_order
#define ook order_of_key
template <typename T>
using oset = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
 
template <typename T>
using ve = vector <T>;
 
template <typename T>
bool umx (T& a, T b) { return a < b ? a = b, 1 : 0; }
 
template <typename T>
bool umn (T& a, T b) { return a > b ? a = b, 1 : 0; }
 
using ll = long long;
using ld = long double;
using pll = pair <ll, ll>;
using pii = pair <int, int>;
using ull = unsigned long long;
 
const int oo = 1e9;
const ll OO = 1e18;
const int N = 3e5 + 10;
const int M = 5e3 + 100;
const int mod = 1e9 + 7;
const bool TEST = 0;


ve <pii> G[N];
ve <pii> NG[N];
vector<int> find_reachable(vector <int> r, vector <int> u, vector <int> v, vector <int> c) {
	int n = sz(r);
	vector<int> ans(n, 1);
	ve <int> C(n, 0);
	for (int i = 0; i < sz(u); i++) {
		G[u[i]].pb({v[i], c[i]});
		G[v[i]].pb({u[i], c[i]});
	}
	for (int i = 0; i < n; i++) {
		set <pii> E;
		ve <bool> vis(n, 0);
		ve <bool> have(n, 0);
		queue <int> q;
		q.push(i);
		while (sz(q)) {
			C[i]++;
			int u = q.front();
			q.pop();
			have[r[u]] = 1;
			for (auto [to, clr] : G[u]) if (!vis[to]) {
				if (have[clr]) {
					vis[to] = 1;
					q.push(to);
				} else {
					E.insert({clr, to});
				}
			}
			while (1) {
				auto it = E.lower_bound(make_pair(r[u], -1));
				if (it != E.end() && (*it).fi == r[u]) {
					if (!vis[(*it).se]) {
						vis[(*it).se] = 1;
						q.push((*it).se);
					}
					E.erase(it);
				} else {
					break;
				}
			}
		}
	}

	int mn = *min_element(all(C));
	for (int i = 0; i < n; i++) {
		if(C[i] == mn) ans[i] = 1;
		else ans[i] = 0;
	}
	return ans;
}

• Subtask 1: 9 / 9
• Subtask 2: 11 / 11
• Subtask 3: 17 / 17
• Subtask 4: 0 / 30
• Subtask 5: 0 / 33