| # | 제출 시각 | 아이디 | 문제 | 언어 | 결과 | 실행 시간 | 메모리 | 
|---|---|---|---|---|---|---|---|
| 813438 | farhan132 | 결혼 문제 (IZhO14_marriage) | C++17 | 502 ms | 4052 KiB | 
이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
/***Farhan132***/
// #pragma GCC optimize("Ofast,fast-math")
// #pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,avx2,fma")
// #pragma GCC optimization ("unroll-loops")
#include <bits/stdc++.h>
using namespace std;
 
typedef long long ll;
typedef double dd;
typedef pair<ll , ll> ii;
typedef tuple < ll,  ll, ll > tp;
 
#define ff first
#define ss second
#define pb push_back
#define in insert
#define bug printf("**!\n")
#define mem(a , b) memset(a, b ,sizeof(a))
#define front_zero(n) __builtin_clz(n)
#define back_zero(n) __builtin_ctzll(n)
#define total_one(n) __builtin_popcount(n)
#define clean fflush(stdout)
 
const ll mod =  (ll) 998244353;
// const ll mod =  (ll) 1e9 + 7;
const ll inf = numeric_limits<int>::max()-5;
const ll INF = (ll)2e18;
 
ll dx[]={0,1,0,-1};
ll dy[]={1,0,-1,0};
ll dxx[]={0,1,0,-1,1,1,-1,-1};
ll dyy[]={1,0,-1,0,1,-1,1,-1};
 
mt19937 rng(chrono::system_clock::now().time_since_epoch().count());
 
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace __gnu_pbds;
 
template <typename T> using ordered_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
const ll N = 32005;
ll mt[N], vis[N];
vector < ll > v[N];
bool kuhn(ll node, ll L, ll R){
    if(vis[node]) return 0;
    vis[node] = 1;
    for(auto u : v[node]){
        if(u < L || u > R) continue;
        if(mt[u] == -1 || kuhn(mt[u], L, R)){
            mt[u] = node;
            return 1;
        }
    }
    return 0;
}
ll T(ll x){
    return (x * (x + 1)) / 2;
}
void solve(){
    ll n, m, k; cin >> n >> m >> k;
    for(ll i = 1; i <= k; i++){
        ll x, y; cin >> x >> y;
        v[x + m].pb(y);
        v[y].pb(x + m);
    }
    ll l = 1, r = n;
    k = n + 1;
    while(l <= r){
        ll mid = (l + r) / 2;
        mem(mt, -1); bool f = 1;
        for(ll i = 1; i <= m; i++){
            for(ll j = 1; j <= m; j++) vis[j] = 0;
            if(!kuhn(i, m + 1, m + mid)){
                f = 0;
                break;
            } 
        }
        if(f == 0){
            l = mid + 1;
        }else{
            k = mid;
            r = mid - 1;
        }
    }
    if(k == n + 1){
        cout << "0\n";
        return;
    }
    mem(mt, -1);
    for(ll i = 1; i <= m; i++){
        for(ll j = 1; j <= m; j++) vis[j] = 0;
        kuhn(i, m + 1, m + k);
    }
    ll ans = n + 1 - k;
    for(ll i = 1; i < n; i++){
        if(mt[i + m] == -1){
            ans += n + 1 - k;
            continue;
        }
        ll node = mt[i + m]; mt[i + m] = -1;
        bool f = 0;
        while(k <= n){
            for(ll j = 1; j <= m; j++) vis[j] = 0;
            if(kuhn(node, m + i + 1, m + k)){
                f = 1;
                break;
            }
            k++;
        }
        if(!f) break;
        ans += n + 1 - k;
    }
    cout << ans << '\n';
    
    
   return;
}
int main() {
    #ifdef LOCAL
        freopen("in.txt", "r", stdin);
        freopen("out.txt", "w", stdout);
        auto start_time = clock();
    #else
         // freopen("subsequence.in", "r", stdin);
         // freopen("subsequence.out", "w", stdout); 
         ios_base::sync_with_stdio(0); cin.tie(NULL); cout.tie(NULL);
    #endif
    //precalc();
 
    ll T = 1, CT = 0; //cin >> T; 
 
    while(T--){
        // cout << "Case #" << ++CT << ": ";
        solve();
    }
    
    #ifdef LOCAL
        auto end_time = clock();
        cerr<< "Execution time: "<<(end_time - start_time)*(int)1e3/CLOCKS_PER_SEC<<" ms\n";
    #endif
 
    return 0;
} 
컴파일 시 표준 에러 (stderr) 메시지
| # | Verdict | Execution time | Memory | Grader output | 
|---|---|---|---|---|
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