Submission #813264

#TimeUsernameProblemLanguageResultExecution timeMemory
813264GrindMachineAbracadabra (CEOI22_abracadabra)C++17
10 / 100
539 ms524288 KiB
// Om Namah Shivaya #include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> using namespace std; using namespace __gnu_pbds; template<typename T> using Tree = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>; typedef long long int ll; typedef long double ld; typedef pair<int, int> pii; typedef pair<ll, ll> pll; #define fastio ios_base::sync_with_stdio(false); cin.tie(NULL) #define pb push_back #define endl '\n' #define sz(a) a.size() #define setbits(x) __builtin_popcountll(x) #define ff first #define ss second #define conts continue #define ceil2(x, y) ((x + y - 1) / (y)) #define all(a) a.begin(), a.end() #define rall(a) a.rbegin(), a.rend() #define yes cout << "Yes" << endl #define no cout << "No" << endl #define rep(i, n) for(int i = 0; i < n; ++i) #define rep1(i, n) for(int i = 1; i <= n; ++i) #define rev(i, s, e) for(int i = s; i >= e; --i) #define trav(i, a) for(auto &i : a) template<typename T> void amin(T &a, T b) { a = min(a, b); } template<typename T> void amax(T &a, T b) { a = max(a, b); } #ifdef LOCAL #include "debug.h" #else #define debug(x) 42 #endif /* */ const int MOD = 1e9 + 7; const int N = 1e5 + 5; const int inf1 = int(1e9) + 5; const ll inf2 = ll(1e18) + 5; void solve(int test_case) { ll n,q; cin >> n >> q; vector<ll> a(n); rep(i,n) cin >> a[i]; auto oa = a; vector<vector<ll>> here; here.pb(a); while(true){ vector<ll> v1,v2,v3; rep(i,n){ if(i < n/2){ v1.pb(a[i]); } else{ v2.pb(a[i]); } } ll ptr1 = 0, ptr2 = 0; while(ptr1 < n/2 or ptr2 < n/2){ if(ptr1 == n/2){ v3.pb(v2[ptr2++]); } else if(ptr2 == n/2){ v3.pb(v1[ptr1++]); } else{ if(v1[ptr1] < v2[ptr2]){ v3.pb(v1[ptr1++]); } else{ v3.pb(v2[ptr2++]); } } } if(a == v3) break; a = v3; here.pb(a); } while(q--){ ll t,i; cin >> t >> i; amin(t,(ll)sz(here)-1); ll ans = here[t][i-1]; cout << ans << endl; } } int main() { fastio; int t = 1; // cin >> t; rep1(i, t) { solve(i); } return 0; }
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