이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
const int N = 200010;
int a[N];
int st1[4*N];
int st2[4*N];
void Build(int node, int l, int r){
if(l>r)return;
if(l==r){
if(l&1){
st2[node]=a[l];
}
else{
st1[node]=a[l];
}
return;
}
int mid=(l+r)/2;
Build(2*node+1, l, mid);
Build(2*node+2, mid+1, r);
st1[node]=st1[2*node+1]^st1[2*node+2];
st2[node]=st2[2*node+1]^st2[2*node+2];
}
void Update(int node, int l, int r, int ind, int val){
if(l>r || l>ind || r<ind)return;
if(l==r){
if(l&1){
st2[node]=val;
}
else st1[node]=val;
return;
}
else{
int mid=(l+r)/2;
Update(2*node+1, l, mid, ind, val);
Update(2*node+2, mid+1, r, ind, val);
}
st2[node]=st2[2*node+1]^st2[2*node+2];
st1[node]=st1[2*node+1]^st1[2*node+2];
}
int get1(int node, int l, int r, int L, int R){
if(l>R || r<L || l>r){
return 0;
}
else if(l>=L && r<=R){
return st1[node];
}
else{
int mid=(l+r)/2;
return get1(2*node+1, l, mid, L, R)^get1(2*node+2, mid+1, r, L, R);
}
}
int get2(int node, int l, int r, int L, int R){
if(l>R || r<L || l>r){
return 0;
}
else if(l>=L && r<=R){
return st2[node];
}
else{
int mid=(l+r)/2;
return get2(2*node+1, l, mid, L, R)^get2(2*node+2, mid+1, r, L, R);
}
}
int main()
{
ios_base::sync_with_stdio(false);
cin.tie(0); cout.tie(0);
int n, q;
cin >> n >> q;
for(int i=0; i< n; i++){
cin >> a[i];
}
Build(0, 0, n-1);
while(q--){
int t;
cin >> t;
if(t==1){
int ind, val;
cin >> ind >> val;
ind--;
Update(0, 0, n-1, ind, val);
}
else{
int l, r;
cin >> l >> r;
r--; l--;
int len=r-l+1;
if(len&1){
if(l&1){
cout << get2(0, 0, n-1, l, r) << '\n';
}
else {
cout << get1(0, 0, n-1, l, r) << '\n';
}
}
else{
cout << 0 << '\n';
}
}
}
}
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