이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include "koala.h"
#include <bits/stdc++.h>
using namespace std;
const int MAX = 1e2 + 42, INF = 1e3 + 42;
int n, w, perm[MAX];
int minValue(int N, int W) {
// TODO: Implement Subtask 1 solution here.
// You may leave this function unmodified if you are not attempting this
// subtask.
return 0;
}
int maxValue(int N, int W) {
// TODO: Implement Subtask 2 solution here.
// You may leave this function unmodified if you are not attempting this
// subtask.
return 0;
}
int greaterValue(int N, int W) {
// TODO: Implement Subtask 3 solution here.
// You may leave this function unmodified if you are not attempting this
// subtask.
return 0;
}
int simulate(int cost, deque<int> other, deque<int> act) {
int stone = w, sum = 0, nb = 0;
while((stone % cost) != 0 && other[0] != 0) {
stone--;
other.pop_front();
}
for(int i = 0; i < cost && other[i]; i++)
sum += other[i];
while(stone >= cost && (act[0] != 0 || other[0] != 0)) {
if(sum < act[0]) {
nb++;
stone -= cost;
act.pop_front();
} else {
sum = 0;
for(int i = 0; i < cost && other[0]; i++) {
stone--;
other.pop_front();
}
for(int i = 0; i < cost && other[i]; i++)
sum += other[i];
}
}
return nb;
}
void DPR(int left, int right, vector<int> pos) {
if(pos.empty()) return;
if(left == right) {
perm[pos[0]] = left;
return;
}
deque<int> other, act;
act.push_back(0);
other.push_back(0);
for(int i = 1; i <= n; i++) {
if(i < left || i > right)
other.push_front(i);
else
act.push_front(i);
}
int sz = (int)pos.size(), nb = 0, best = INF;
for(int i = 1; i * sz <= w; i++) {
int chosen = simulate(i+1, other, act);
if(abs(sz - 2 * chosen) < best) {
nb = i;
best = abs(sz - 2 * chosen);
}
if(chosen == 0)
i = w + 1;
}
int B[n], R[n];
for(int i = 0; i < n; i++)
B[i] = R[i] = 0;
for(int p : pos)
B[p] = nb;
playRound(B, R);
vector<int> posInf, posSup;
for(int p : pos)
if(R[p] >= nb+1)
posSup.push_back(p);
else
posInf.push_back(p);
DPR(left, left - 1 + (int)posInf.size(), posInf);
DPR(left + (int)posInf.size(), right, posSup);
}
void allValues(int N, int W, int *P) {
n = N, w = W;
vector<int> vals, pos;
for(int i = 0; i < n; i++)
pos.push_back(i);
for(int i = 0; i < n; i++)
vals.push_back(i+1);
DPR(1, N, pos);
for(int i = 0; i < n; i++)
P[i] = perm[i];
}
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