제출 #808698

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
808698		vjudge1	코알라 (JOI13_koala)	C++17	0 / 100	108 ms	3548 KiB

koala

#include <bits/stdc++.h>
#define fi first
#define se second
#define ll long long
#define pii pair<int,int>
#define pll pair<ll,ll>
#define pill pair<int,ll>
#define mem(a, b) memset(a, b, sizeof(a))
#define MASK(i) (1LL << (i))
#define BIT(x, i) (((x) >> (i)) & 1)
#define name "test"

using namespace std;

const int N = 1e5 + 5;
const int mod = 1e9 + 7;
const ll oo = 1e18;

template <typename T1, typename T2> bool maxi(T1 &a, T2 b){if (a < b){a = b; return 1;} return 0;}
template <typename T1, typename T2> bool mini(T1 &a, T2 b){if (a > b){a = b; return 1;} return 0;}

struct SEGTREE{
	ll val[N << 2];
	SEGTREE(){};
	void update(int id, int l, int r, int i, ll x){
		if (l > i || r < i) return;
		if (l == r) return void(val[id] = x);
		int m = (l + r) >> 1;
		if (m >= i) update(id << 1, l, m, i, x);
		else update(id << 1 | 1, m + 1, r, i, x);
		val[id] = max(val[id << 1], val[id << 1 | 1]);
	}

	ll get(int id, int l, int r, int u, int v){
		if (l > v || r < u) return -oo;
		if (l >= u && r <= v) return val[id];
		int m = (l + r) >> 1;
		return max(get(id << 1, l, m, u, v), get(id << 1 | 1, m + 1, r, u, v));
	}
} ST;
int s, t;
int limDis, downPower, n;
int b[N];
pii a[N];

void input(){
	cin >> s >> t >> limDis >> downPower >> n;
	for (int i = 1; i <= n; i++)
		cin >> a[i].fi >> a[i].se; 
}

void prepare(){
	sort(a + 1, a + n + 1);
	for (int i = 1; i <= n; i++)
		b[i] = a[i].fi;
}

void solveUp(){
	prepare();
	int pre_place = s;
	b[0] = s;
	for (int i = 1; i <= n; i++){
		int k = (b[i] - pre_place) / limDis + ((b[i] - pre_place) % limDis > 0);
		ll res = -oo;
		for (int j = k; j <= k + 1; j++){
			int id = lower_bound(b, b + n + 1, b[i] - j * limDis) - b;
			ll tmp = ST.get(1, 0, n, id, i - 1) - downPower * j;
			// if (i == 2)
			// 	cout << j << ' ' << id << ' ' << tmp << '\n';
			maxi(res, tmp + a[i].se);
		}
		// cout << i << ' ' << k << " " << res << '\n';
		ST.update(1, 0, n, i, res);
		pre_place = b[i];
		// if (i == 1)
		// 	for (int j = 0; j <= 1; j++)
		// 		cout << ST.get(1, 0, n, j, j) << ' ';
	}

	int k = (t - pre_place) / limDis + ((t - pre_place) % limDis > 0);
	ll ans = -oo;
	for (int j = k; j <= k + 1; j++){
		int id = lower_bound(b, b + n + 1, t - j * limDis) - b;
		ll tmp = ST.get(1, 0, n, id, n) - j * downPower;
		maxi(ans, tmp);
	}
	cout << ans;
}

int main(){
	// load();
	input();
	solveUp();
}

• Subtask 1: 0 / 20
• Subtask 2: 0 / 30
• Subtask 3: 0 / 50