Submission #807373

#	Time	Username	Problem	Language	Result	Execution time	Memory
807373		Benmath	Rectangles (IOI19_rect)	C++14	10 / 100	790 ms	480 KiB

rect

#include "rect.h"
#include <cstdio>
#include <unistd.h>
#include <cassert>
#include <string>
#include<bits/stdc++.h>
using namespace std;
int treemax[10001];
int treemin[10001];
void updatemax(int node,int start,int end,int idx,int val){
if(start==end){
treemax[node]=val;
}else{
int mid=(start+end)/2;
if(start<=idx and idx<=mid){
updatemax(2*node,start,mid,idx,val);
}else{
updatemax(2*node+1,mid+1,end,idx,val);
}
 
treemax[node]=max(treemax[2*node],treemax[2*node+1]);
}
}
void updatemin(int node,int start,int end,int idx,int val){
if(start==end){
treemin[node]=val;
}else{
int mid=(start+end)/2;
if(start<=idx and idx<=mid){
updatemin(2*node,start,mid,idx,val);
}else{
updatemin(2*node+1,mid+1,end,idx,val);
}
 
treemin[node]=min(treemin[2*node],treemin[2*node+1]);
}
}
int querymax(int node,int start,int end,int l,int r){
if(l>end or r<start){
return 0;
}
if(l<=start and end<=r){
return treemax[node];
}
int mid=(start+end)/2;
return max(querymax(2*node,start,mid,l,r),querymax(2*node+1,mid+1,end,l,r));
}
int querymin(int node,int start,int end,int l,int r){
if(l>end or r<start){
return 1e9;
}
if(l<=start and end<=r){
return treemin[node];
}
int mid=(start+end)/2;
return min(querymin(2*node,start,mid,l,r),querymin(2*node+1,mid+1,end,l,r));
}
long long count_rectangles(std::vector<std::vector<int> > a) {
    int m=a[0].size();
    int n=a.size();
    
    if(n<=2 or m<=2){
        return 0;
    }
    if(n<=3){
    for(int i=0;i<m;i++){
        if(a[1][i]<a[0][i] and a[1][i]<a[2][i]){
            updatemin(1,0,m-1,i,1);
        }
        updatemax(1,0,m-1,i,a[1][i]);
    }
    int ans=0;
    for(int j=1;j<(m-1);j++){
        for(int k=j;k<(m-1);k++){
            int x=querymin(1,0,m-1,j,k);
            if(x==1){
                int y=querymax(1,0,m-1,j,k);
                if(y<a[1][j-1] and y<a[1][k+1]){
                    ans++;
                }
            }
        }
    }
    return ans;
    }else{
        int ans=0;
        int pref[m][n];
        int dolje[n][m];
        int desno[n][m];
        
        for(int i=0;i<n;i++){
            for(int j=m-1;j>=0;j--){
                if(a[i][j]==1){
                    desno[i][j]=j;
                }else{
                    if(j==(m-1)){
                        desno[i][j]=-1;
                    }else{
                        desno[i][j]=desno[i][j+1];
                    }
                }
            }
        }
        for(int j=0;j<m;j++){
            for(int i=n-1;i>=0;i--){
                if(a[i][j]==1){
                    dolje[i][j]=i;
                }else{
                    if(i==(n-1)){
                        dolje[i][j]=-1;
                    }else{
                        dolje[i][j]=dolje[i+1][j];
                    }
                }
            }
        }
        for(int j=0;j<m;j++){
            for(int i=0;i<n;i++){
                if(i==0){
                    pref[j][i]=a[i][j];
                }else{
                    pref[j][i]=pref[j][i-1]+a[i][j];
                }
            }
        }
        for(int i=1;i<(n-1);i++){
            for(int j=1;j<(m-1);j++){
                if(a[i-1][j]==1 and a[i][j]==0 and a[i][j-1]==1){
                    int t1=0;
                    int i1=dolje[i][j];
                    int j1=desno[i][j];
                    for(int k=i;k<dolje[i][j];k++){
                        for(int t=j;t<desno[i][j];t++){
                            if(a[k][t]!=0){
                                t1++;
                                break;
                            }
                            if(a[i-1][t]!=1 or a[i1][t]!=1){
                                t1++;
                                break;
                            }
                            if(a[k][j-1]!=1 or a[k][j1]!=1){
                                t1++;
                                break;
                            }
                        }
                    }
                    if(t1==0){
                        ans++;
                    }
                }
            }
        }
        return ans;
    }
}

• Subtask 1: 0 / 8
• Subtask 2: 0 / 7
• Subtask 3: 0 / 12
• Subtask 4: 0 / 22
• Subtask 5: 10 / 10
• Subtask 6: 0 / 13
• Subtask 7: 0 / 28