이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
// In the name of Allah
#include <bits/stdc++.h>
#include "books.h"
using namespace std;
typedef long long int ll;
typedef long double ld;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;
#define all(x) (x).begin(),(x).end()
#define len(x) ((ll) (x).size())
#define F first
#define S second
#define pb push_back
#define sep ' '
#define endl '\n'
#define Mp make_pair
#define debug(x) cerr << #x << ": " << x << endl;
#define kill(x) cout << x << '\n', exit(0)
#define set_dec(x) cout << fixed << setprecision(x);
#define file_io(x,y) freopen(x, "r", stdin); freopen(y, "w", stdout);
const int maxn = 1e6 + 4;
ll arr[maxn]; set<int> res;
void answerx() {
vector<int> vc;
for (int i : res) vc.pb(i);
answer(vc);
}
void solve(int N, int K, ll A, int S) {
ll sm = 0;
for (int i = 1; i <= K; i++) {
arr[i] = skim(i); sm += arr[i];
res.insert(i);
}
if (sm >= A && sm <= 2 * A) answerx();
else if (sm > 2 * A) impossible();
sm -= arr[K]; res.erase(K);
int l = K, r = N + 1;
while (r - l > 1) {
int mid = (l + r) / 2;
arr[mid] = skim(mid);
if (sm + arr[mid] <= 2 * A) l = mid;
else r = mid;
}
sm += arr[l]; res.insert(l);
int i = K - 1, j = l - 1;
while (i >= 1 && (sm < A || sm > 2 * A)) {
arr[j] = skim(j);
sm -= arr[i]; res.erase(i); i--;
sm += arr[j]; res.insert(j); j--;
}
if (sm >= A && sm <= 2 * A) answerx();
else impossible();
}
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