Submission #807116

#TimeUsernameProblemLanguageResultExecution timeMemory
807116GrindMachineBuilding 4 (JOI20_building4)C++17
100 / 100
203 ms68900 KiB
// Om Namah Shivaya #include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> using namespace std; using namespace __gnu_pbds; template<typename T> using Tree = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>; typedef long long int ll; typedef long double ld; typedef pair<int, int> pii; typedef pair<ll, ll> pll; #define fastio ios_base::sync_with_stdio(false); cin.tie(NULL) #define pb push_back #define endl '\n' #define sz(a) a.size() #define setbits(x) __builtin_popcountll(x) #define ff first #define ss second #define conts continue #define ceil2(x, y) ((x + y - 1) / (y)) #define all(a) a.begin(), a.end() #define rall(a) a.rbegin(), a.rend() #define yes cout << "Yes" << endl #define no cout << "No" << endl #define rep(i, n) for(int i = 0; i < n; ++i) #define rep1(i, n) for(int i = 1; i <= n; ++i) #define rev(i, s, e) for(int i = s; i >= e; --i) #define trav(i, a) for(auto &i : a) template<typename T> void amin(T &a, T b) { a = min(a, b); } template<typename T> void amax(T &a, T b) { a = max(a, b); } #ifdef LOCAL #include "debug.h" #else #define debug(x) 42 #endif /* refs: https://codeforces.com/blog/entry/74871?#comment-590839 proof for lemma and a nicer way to think about the problem => https://codeforces.com/blog/entry/74871?#comment-590887 */ const int MOD = 1e9 + 7; const int N = 1e5 + 5; const int inf1 = int(1e9) + 5; const ll inf2 = ll(1e18) + 5; void solve(int test_case) { ll n; cin >> n; vector<ll> a(2*n+5), b(2*n+5); rep1(i,2*n) cin >> a[i]; rep1(i,2*n) cin >> b[i]; pll dp[2*n+5][2]; rep(i,2*n+5) rep(j,2) dp[i][j] = {inf2,-inf2}; dp[0][0] = {0,0}; rep1(i,2*n){ rep(x,2){ rep(y,2){ ll v1 = a[i], v2 = a[i-1]; if(x) v1 = b[i]; if(y) v2 = b[i-1]; if(v1 >= v2){ amin(dp[i][x].ff,dp[i-1][y].ff+(x^1)); amax(dp[i][x].ss,dp[i-1][y].ss+(x^1)); } } } } ll x = -1; rep(j,2){ if(dp[2*n][j].ff <= n and dp[2*n][j].ss >= n){ x = j; } } if(x == -1){ cout << -1 << endl; return; } string ans = ""; ll want = n; rev(i,2*n,1){ if(!x) ans.pb('A'), want--; else ans.pb('B'); bool ok = false; rep(y,2){ ll v1 = a[i], v2 = a[i-1]; if(x) v1 = b[i]; if(y) v2 = b[i-1]; if(v1 >= v2){ if(dp[i-1][y].ff <= want and dp[i-1][y].ss >= want){ x = y; ok = true; break; } } } assert(ok); } assert(want == 0); reverse(all(ans)); cout << ans << endl; } int main() { fastio; int t = 1; // cin >> t; rep1(i, t) { solve(i); } return 0; }
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