#include <bits/stdc++.h>
using namespace std;
#define fi first
#define se second
#define pb push_back
typedef long long ll;
typedef pair<int, int> ii;
typedef vector<int> vi;
int N;
vector<ii> edges;
vi adj[100005];
int subtree_size[100005];
bool vis[100005];
void dfs(int n) {
vis[n] = true;
subtree_size[n] = 1;
for (int i : adj[n]) {
if (!vis[i]) {
dfs(i);
subtree_size[n] += subtree_size[i];
}
}
}
bool vis2[100005];
int dfs2(int n) {
// cout<<"at "<<n<<endl;
vis2[n] = true;
bool works = true;
for (int i : adj[n]) {
if (!vis2[i]) {
if (subtree_size[i] > N / 2) {
works = false;
return dfs2(i);
}
}
}
if (works) {
// cout<<"yay "<<n<<endl;
return n;
}
return -1;
}
vi order;
bool vis3[100005];
void dfs3(int n) {
vis3[n] = true;
order.pb(n);
for (int i : adj[n]) {
if (!vis3[i]) {
dfs3(i);
}
}
}
int main() {
cin>>N;
for (int i = 0; i < N - 1; i++) {
int u, v;
cin>>u>>v;
u--; v--;
edges.pb({u, v});
adj[u].pb(v);
adj[v].pb(u);
}
dfs(0);
/*
cout<<"subtree size: ";
for (int i = 0; i < N; i++) {
cout<<subtree_size[i]<<" ";
}
cout<<endl;
*/
ll total = 0;
for (int i = 0; i < N - 1; i++) {
int u = edges[i].fi;
int v = edges[i].se;
if (subtree_size[u] < subtree_size[v]) // u is parent of v
swap(u, v);
total += min(subtree_size[v], N - subtree_size[v]);
}
total *= 2;
int centroid = dfs2(0); // find centroid
// cout<<"centroid: "<<centroid<<endl;
dfs3(centroid); // need order
/*
cout<<"order: ";
for (int i : order)
cout<<i<<" ";
cout<<endl;
*/
int ans[N];
if (N % 2 == 0) {
for (int i = 0; i < N / 2; i++) {
ans[order[i]] = order[i + N / 2];
ans[order[i + N / 2]] = order[i];
}
}
else {
ans[order[0]] = order[0];
for (int i = 0; i < N / 2; i++) {
ans[order[i + 1]] = order[i + N / 2 + 1];
ans[order[i + N / 2 + 1]] = order[i + 1];
}
swap(ans[order[0]], ans[order[1]]);
}
// cout<<"ANSWER: "<<endl;
cout<<0<<endl;
for (int i = 0; i < N; i++) {
cout<<1<<" ";
}
cout<<endl;
cout<<total<<endl;
for (int i = 0; i < N; i++) {
cout<<(ans[i] + 1)<<" ";
}
cout<<endl;
}
// find centroid, do dfs order, then map i to i + N / 2
// only important is that start and end never belong to same tree
// n = 8: (1, 2, 3, 4) <=> (5, 6, 7, 8)
// n = 9: (2, 3, 4, 5) <=> (6, 7, 8, 9), then swap the "goto" for
// 1 and 2 (then 1 -> 1 and 2 -> 6 becomes 1 -> 6 and 2 -> 1)
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Incorrect |
1 ms |
2656 KB |
Integer parameter [name=vi] equals to 8, violates the range [1, 4] |
2 |
Halted |
0 ms |
0 KB |
- |
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Incorrect |
2 ms |
2660 KB |
Integer parameter [name=vi] equals to 2186, violates the range [1, 256] |
2 |
Halted |
0 ms |
0 KB |
- |
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Incorrect |
1 ms |
2656 KB |
Integer parameter [name=vi] equals to 8, violates the range [1, 4] |
2 |
Halted |
0 ms |
0 KB |
- |