이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include "cyberland.h"
#include <bits/stdc++.h>
#define ll long long
#define pii pair<int, int>
using namespace std;
const ll oo = 1e18;
const int MAX = 1e5 + 5;
struct edge{
int u, c;
};
int n, k, f;
int A[MAX];
vector<edge> g[MAX];
bool visited[MAX];
vector<int> starts;
void dfs(int node){
visited[node] = 1;
for(auto& e:g[node]){
if(visited[e.u]) continue;
dfs(e.u);
}
}
double dist[MAX][32];
bool comp(pii a, pii b){
return dist[a.first][a.second] <= dist[b.first][b.second];
}
void dijkstra(){
set<pii, decltype(&comp)> st(&comp);
for (int i = 0; i < n; i++)
{
for (int j = 0; j <= k; j++)
{
dist[i][j] = oo;
}
}
for(int a:starts){
dist[a][k] = 0;
st.insert({a, k});
}
while(!st.empty()){
int node = st.begin()->first;
int l = st.begin()->second;
double d = dist[node][l];
st.erase(st.begin());
for(auto& e:g[node]){
double b = d + e.c;
if(b < dist[e.u][l]){
st.erase({e.u, l});
dist[e.u][l] = b;
st.insert({e.u, l});
}
if(l == 0 || A[e.u] != 2) continue;
if(b / 2 < dist[e.u][l - 1]){
st.erase({e.u, l - 1});
dist[e.u][l - 1] = b / 2;
st.insert({e.u, l - 1});
}
}
}
}
double solve(int N, int M, int K, int H, vector<int> x, vector<int> y, vector<int> c, vector<int> arr) {
n = N;
k = K;
f = H;
starts.clear();
for (int i = 0; i < n; i++)
{
A[i] = arr[i];
g[i].clear();
visited[i] = 0;
}
for (int i = 0; i < M; i++)
{
g[x[i]].push_back({y[i], c[i]});
g[y[i]].push_back({x[i], c[i]});
}
g[f].clear();
dfs(0);
starts.push_back(0);
for (int i = 0; i < n; i++)
{
if(visited[i] && A[i] == 0){
starts.push_back(i);
}
}
dijkstra();
double ans = oo;
for(int i = 0; i <= k; ++i){
ans = min(ans, dist[f][i]);
}
if(ans == oo){
return -1;
}
else{
return ans;
}
}
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