제출 #805773

#제출 시각아이디문제언어결과실행 시간메모리
805773YesPyCutting a rectangle (LMIO18_staciakampis)C++17
0 / 100
1066 ms332 KiB
#include <bits/stdc++.h> #pragma GCC optimize("unroll-loops") #pragma inline_recursion(on) #pragma GCC optimize("O2") // #pragma GCC optimize("Ofast") #define ff first #define ss second #define tcT template<class T #define fastio ios::sync_with_stdio(false);cin.tie(nullptr); #define ln '\n' #define nwln cout<<ln; using namespace std; tcT> using vr = vector<T>; using pi = pair<int, int>; using vi = vr<int>; using vpi = vr<pi>; using ll = long long; using oo = bool; #define maxs(i, j) (i = max(i, j)) #define fri(i,a,b) for(int i=(a); i<(b); ++i) #define each(x, a) for(auto& x: a) #define sz(x) int((x).size()) #define bg(x) begin(x) #define all(x) bg(x), end(x) #define sr(x) sort(all(x)) #define phb push_back #define ppb pop_back #define eb emplace_back const int MX = (int) 3e5+3; int K; set<int> ans; vpi config; inline void go(vpi rec) { // cout<<"New instance of GO"<<ln; // each(x, rec) cout<<x.ff<<", "<<x.ss<<ln; // nwln if(sz(rec) == 1) ans.insert(min(rec[0].ff, rec[0].ss)); pi t[2]; t[0] = rec.back(), rec.ppb(); t[1] = rec.back(), rec.ppb(); pi flag[2]; flag[0] = flag[1] = {-1, -1}; if(t[0].ff == t[1].ff) { flag[0] = {t[0].ff, t[0].ss + t[1].ss}; if(flag[0].ff < flag[0].ss) swap(flag[0].ff, flag[0].ss); } if(t[0].ss == t[1].ss) { flag[1] = {t[0].ff + t[1].ff, t[0].ss}; if(flag[1].ff < flag[1].ss) swap(flag[1].ff, flag[1].ss); } if(flag[0].ff != -1) { rec.eb(flag[0]); go(rec); rec.ppb(); } if(flag[1].ff != -1) { rec.eb(flag[1]); go(rec); rec.ppb(); } swap(t[1].ff, t[1].ss); flag[0] = flag[1] = {-1, -1}; if(t[0].ff == t[1].ff) { flag[0] = {t[0].ff, t[0].ss + t[1].ss}; if(flag[0].ff < flag[0].ss) swap(flag[0].ff, flag[0].ss); } if(t[0].ss == t[1].ss) { flag[1] = {t[0].ff + t[1].ff, t[0].ss}; if(flag[1].ff < flag[1].ss) swap(flag[1].ff, flag[1].ss); } if(flag[0].ff != -1) { rec.eb(flag[0]); go(rec); rec.ppb(); } if(flag[1].ff != -1) { rec.eb(flag[1]); go(rec); rec.ppb(); } } int main() { fastio cin>>K; while(K--) { int a, b; cin>>a>>b; config.eb(a, b); } do { go(config); } while(next_permutation(all(config))); cout<<sz(ans)<<ln; each(x, ans) cout<<x<<ln; return 0; } /* For subtask 2 basically is the following: For each DIV divisor of SUM := a1+...+ak, check if it's possible to partition the set {a1, ..., ak} into subsets having sum = DIV If it's possible, print min(DIV, SUM/DIV) But idk how to do it efficiently, yet! */

컴파일 시 표준 에러 (stderr) 메시지

staciakampis.cpp:3: warning: ignoring '#pragma inline_recursion ' [-Wunknown-pragmas]
    3 | #pragma inline_recursion(on)
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