제출 #800120

#제출 시각아이디문제언어결과실행 시간메모리
800120TB_Joker (BOI20_joker)C++17
0 / 100
208 ms63692 KiB
#include <bits/stdc++.h> using namespace std; // #undef _GLIBCXX_DEBUG // disable run-time bound checking, etc // #pragma GCC optimize("Ofast,inline") // Ofast = O3,fast-math,allow-store-data-races,no-protect-parens // #pragma GCC optimize ("unroll-loops") // #pragma GCC target("bmi,bmi2,lzcnt,popcnt") // bit manipulation // #pragma GCC target("movbe") // byte swap // #pragma GCC target("aes,pclmul,rdrnd") // encryption // #pragma GCC target("avx,avx2,f16c,fma,sse3,ssse3,sse4.1,sse4.2") // SIMD // #include <bits/extc++.h> // using namespace __gnu_pbds; // template<class T>using ordered_set = tree<T, null_type, less<T>, rb_tree_tag,tree_order_statistics_node_update>; // template<class T>using ordered_multiset = tree<T, null_type, less_equal<T>, rb_tree_tag,tree_order_statistics_node_update>; #define ll long long #define INF (ll)1e9+7 #define fo(i, n) for(int i=0;i<((ll)n);i++) #define deb(x) cout << #x << " = " << x << endl; #define deb2(x, y) cout << #x << " = " << x << ", " << #y << " = " << y << endl #define pb push_back #define mp make_pair #define F first #define S second #define LSOne(S) ((S) & (-S)) #define all(x) x.begin(), x.end() #define rall(x) x.rbegin(), x.rend() inline int readint(){ int v = 0; char c; while((c = getchar()) != EOF && c != ' ' && c != '\n'){ v *= 10; v += c - '0'; } return v; } inline int readintsigned() { int v = 0; int sign = 1; char c = getchar(); if (c == '-') { sign = -1; } else { v += c - '0'; } while ((c = getchar()) != EOF && c != ' ' && c != '\n') { v *= 10; v += c - '0'; } return v * sign; } inline string readstring() { string s; char c; while ((c = getchar()) != EOF && c != '\n' && c != ' ') { s.push_back(c); } return s; } template <class result_t=std::chrono::milliseconds,class clock_t=std::chrono::steady_clock,class duration_t = std::chrono::milliseconds> auto since(std::chrono::time_point<clock_t, duration_t> const& start){return std::chrono::duration_cast<result_t>(clock_t::now() - start);} typedef pair<int, int> pii; typedef pair<ll, ll> pl; typedef vector<int> vi; typedef vector<ll> vl; typedef vector<pii> vpii; typedef vector<pl> vpl; typedef vector<vi> vvi; typedef vector<vl> vvl; typedef vector<vpii> vvpii; typedef vector<vpl> vvpl; struct UnionFind{ vl degree, height, p, siz; vector<vvpl> updates; // pUpdates, heightUpdate, sizUpdate vi possibleUpdate; int n; int possible = 0; UnionFind(int n) : n(n) { height.assign(n, 0); degree.assign(n, 0); p.assign(n, 0); siz.assign(n, 1); fo(i, n) p[i] = i; } int find(int x){ if(x == p[x]) return x; updates[updates.size()-1][0].pb({x, p[x]}); updates[updates.size()-1][1].pb({x, height[x]}); int res = find(p[x]); height[x] = height[p[x]]+1; return p[x] = res; } void addEdge(int a, int b){ possibleUpdate.pb(possible); updates.pb({{}, {}, {}}); int a2 = find(a); int b2 = find(b); if(a2==b2){ if(height[a]%2 == height[b]%2) possible++; }else{ if(siz[b2] > siz[a2]) swap(a, b); updates[updates.size()-1][2].pb({a, siz[a]}); updates[updates.size()-1][0].pb({b, p[b]}); siz[a] += siz[b]; p[b] = a; } } void backtrack(){ possible = possibleUpdate[possibleUpdate.size()-1]; for(auto up : updates[possibleUpdate.size()-1][0]) p[up.F] = up.S; for(auto up : updates[possibleUpdate.size()-1][1]) height[up.F] = up.S; for(auto up : updates[possibleUpdate.size()-1][2]) siz[up.F] = up.S; updates.pop_back(); possibleUpdate.pop_back(); } }; int main() { // cout << fixed << setprecision(20); // auto start = std::chrono::steady_clock::now(); // since(start).count() cin.tie(0)->sync_with_stdio(0); int n, m, q, from, to, que; vpl edges; cin >> n >> m >> q; fo(i, m){ cin >> from >> to; edges.pb({from-1, to-1}); } vector<vector<tuple<int, int, int>>> queries(1000); fo(x, q){ cin >> from >> to; queries[from/((int)sqrt(n))].pb({to-1, from-1, x}); } fo(i, 1000){ sort(rall(queries[i])); } UnionFind uf(n); vi ans(q, 0); fo(section, 1000){ int lo = 0, hi = m-1; for(auto query : queries[section]){ tie(to, from, que) = query; fo(i, hi-to) uf.addEdge(edges[hi-i].F,edges[hi-i].S); hi=to; fo(i, from-lo) uf.addEdge(edges[lo+i].F, edges[lo+i].S); if(uf.possible) ans[que] = 1; fo(i, from-((int)sqrt(n))*section) uf.backtrack(); lo = ((int)sqrt(n))*section; } while(uf.possibleUpdate.size()) uf.backtrack(); } fo(i, q) cout << (ans[i]?"YES\n":"NO\n"); return 0; }
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