This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include "highway.h"
#include <bits/stdc++.h>
using namespace std;
#define ll long long
#define pb push_back
#define F first
#define S second
#define INF 1e18
#define all(v) (v).begin(),(v).end()
#define rall(v) (v).rbegin(),(v).rend()
#define pii pair<int,int>
#define pll pair<ll,ll>
#define OK cout<<"Ok"<<endl;
#define MOD (ll)(1e9+7)
const int mxn=1e5+5;
int n,m,a,b,mx,sz,dis;
vector<int>que;
vector<pii>vt[mxn];
vector<pii>nodes;
void find_dep(int u,int p,int dep){
mx=max(mx,dep);
for(pii pp:vt[u]){
int v=pp.F;
if(v!=p){
find_dep(v,u,dep+1);
}
}
}
void dfs(int u,int p,int dep){
for(pii pp:vt[u]){
int v=pp.F,idx=pp.S;
if(v==p) continue;
if(dep+1<=sz){
que[idx]=1;
}
else{
que[idx]=0;
}
dfs(v,u,dep+1);
}
}
void add_nodes(int u,int p,int dep){
for(pii pp:vt[u]){
int v=pp.F,idx=pp.S;
if(v!=p){
if(dep+1==dis) nodes.pb({v,idx});
add_nodes(v,u,dep+1);
}
}
}
ll check(int x){
sz=x;
dfs(1,-1,0);
ll res=ask(que);
return res;
}
void find_pair(int N, vector<int> ux, vector<int> vx, int A, int B) {
n=N;
a=A,b=B;
m=ux.size();
for(int i=0;i<m;i++){
int u=ux[i]+1,v=vx[i]+1;
vt[u].pb({v,i});
vt[v].pb({u,i});
}
for(int i=0;i<m;i++){
que.pb(1);
}
ll cost=ask(que);
find_dep(1,-1,0);
int l=0,r=mx;
while(l<=r){
int m=(l+r)/2;
if(check(m)<cost){
l=m+1;
}
else{
r=m-1;
}
}
ll cost2=cost/b*a;
dis=l;
add_nodes(1,-1,0);
l=0,r=nodes.size()-1;
while(l<=r){
int mm=(l+r)/2;
for(int i=0;i<m;i++){
que[i]=0;
}
for(int i=l;i<=mm;i++){
que[nodes[i].S]=1;
}
ll res=ask(que);
if(res>cost2){
r=mm-1;
}
else{
l=mm+1;
}
}
r++;
int root=nodes[r].F;
ll cnt=cost/b;
nodes.clear();
dis=cnt;
add_nodes(root,-1,0);
l=0,r=nodes.size()-1;
while(l<=r){
int mm=(l+r)/2;
for(int i=0;i<m;i++){
que[i]=0;
}
for(int i=l;i<=mm;i++){
que[nodes[i].S]=1;
}
ll res=ask(que);
if(res>cost2){
r=mm-1;
}
else{
l=mm+1;
}
}
r++;
int root2=nodes[r].F;
answer(root-1,root2-1);
}
/*
g++ highway.cpp grader.cpp ; .\a.exe
8 7 1 2 5 6
0 1
0 2
1 3
1 4
4 6
6 7
2 5
*/
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