Submission #796967

#TimeUsernameProblemLanguageResultExecution timeMemory
796967GrindMachinePower Plant (JOI20_power)C++17
47 / 100
1592 ms15564 KiB
// Om Namah Shivaya

#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>

using namespace std;
using namespace __gnu_pbds;

template<typename T> using Tree = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
typedef long long int ll;
typedef long double ld;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;

#define fastio ios_base::sync_with_stdio(false); cin.tie(NULL)
#define pb push_back
#define endl '\n'
#define sz(a) a.size()
#define setbits(x) __builtin_popcountll(x)
#define ff first
#define ss second
#define conts continue
#define ceil2(x, y) ((x + y - 1) / (y))
#define all(a) a.begin(), a.end()
#define rall(a) a.rbegin(), a.rend()
#define yes cout << "Yes" << endl
#define no cout << "No" << endl

#define rep(i, n) for(int i = 0; i < n; ++i)
#define rep1(i, n) for(int i = 1; i <= n; ++i)
#define rev(i, s, e) for(int i = s; i >= e; --i)
#define trav(i, a) for(auto &i : a)

template<typename T>
void amin(T &a, T b) {
    a = min(a, b);
}

template<typename T>
void amax(T &a, T b) {
    a = max(a, b);
}

#ifdef LOCAL
#include "debug.h"
#else
#define debug(x) 42
#endif

/*

read edi long time ago, dont exactly remember the approach in the edi

*/

const int MOD = 1e9 + 7;
const int N = 2e5 + 5;
const int inf1 = int(1e9) + 5;
const ll inf2 = ll(1e18) + 5;

vector<ll> adj[N];
vector<ll> a(N);
vector<ll> dp(N);

void dfs(ll u, ll p, ll r){
    dp[u] = 0;

    ll dp1[3], dp2[3];
    memset(dp1,0,sizeof dp1);
    memset(dp2,0,sizeof dp2);

    trav(v,adj[u]){
        if(v == p) conts;
        dfs(v,u,r);

        memset(dp2,0,sizeof dp2);

        rep(j,3){
            rep(k,2){
                ll j2 = min(j+k,2);
                ll add = 0;
                if(k) add = dp[v];
                amax(dp2[j2],dp1[j]+add);
            }
        }

        rep(j,3) dp1[j] = dp2[j];
    }

    if(u != r){
        dp[u] = max(dp1[1],dp1[2]);

        if(a[u]){
            dp[u]--;
            amax(dp[u],1ll);
        }   
    }
    else{
        dp[u] = max(dp1[1]+1,dp1[2]-1);
    }

    amax(dp[u],0ll);
}

void solve(int test_case)
{
    ll n; cin >> n;
    rep1(i,n-1){
        ll u,v; cin >> u >> v;
        adj[u].pb(v), adj[v].pb(u);
    }    

    rep1(i,n){
        char ch; cin >> ch;
        a[i] = ch-'0';
    }

    ll ans = 0;

    rep1(r,n){
        if(!a[r]) conts;
        // if(r != 2) conts;

        dfs(r,-1,r);
        amax(ans,dp[r]);
    }

    cout << ans << endl;
}

int main()
{
    fastio;

    int t = 1;
    // cin >> t;

    rep1(i, t) {
        solve(i);
    }

    return 0;
}
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...