Submission #79639

#	Time	Username	Problem	Language	Result	Execution time	Memory
79639		LeMans	Aliens (IOI16_aliens)	C++14	25 / 100	2063 ms	50044 KiB

aliens

#include "aliens.h"
#include <stdio.h>
#include <bits/stdc++.h>

using namespace std;

typedef double db;
typedef long long ll;
typedef long double ld;
typedef unsigned int ui;
typedef unsigned long long ull;

typedef pair < db, db > pdd;
typedef pair < db, ld > pdl;
typedef pair < ld, db > pld;
typedef pair < ld, ld > ldp;

typedef pair < ll, ll > pll;
typedef pair < int, ll > pil;
typedef pair < ll, int > pli;
typedef pair < int, int > pii;

#define F first
#define S second

#define en end()
#define bg begin()

#define rev reverse
#define mp make_pair
#define pb push_back

#define y1 y1234567890
#define um unordered_map

#define all(x) x.bg, x.en
#define sz(x) (int)x.size()
#define len(x) (int)strlen(x)

#define sqr(x) ((x + 0ll) * (x))
#define sqrd(x) ((x + 0.0) * (x))

#define forn(i, n) for (int i = 1; i <= n; i++)

const ll inf = (ll)1e18;
const ll mod = (ll)1e9 + 7;

const db eps = (db)1e-9;
const db pi = acos(-1.0);

const int dx[] = {0, 0, 1, 0, -1};
const int dy[] = {0, 1, 0, -1, 0};

const int N = 10005;
const int M = 1000500;

ll dp[N][N];
int sz, ar[N], pref[N], pos[N], f[M];

ll take_photos(int n, int m, int lim, vector < int > r, vector < int > c) {
	for (int i = 0; i < n; i++) {
		int L = min(r[i], c[i]);
		int R = max(r[i], c[i]);
		L++, R++;
		ar[++sz] = L;
		ar[++sz] = R;
		f[L] = max(f[L], R);
	}

	sort(ar + 1, ar + 1 + sz);
	sz = unique(ar + 1, ar + 1 + sz) - ar - 1;

	for (int i = 0; i <= sz; i++)
		for (int j = 0; j <= lim; j++)
			dp[i][j] = inf;

	dp[0][0] = 0;

	for (int i = 1; i <= sz; i++) {
		pref[i] = max(pref[i - 1], f[ar[i]]);
		if (pref[i])
			pos[i] = lower_bound(ar + 1, ar + 1 + sz, pref[i]) - ar;
		for (int j = 1; j <= lim; j++) {
			for (int k = 1; k <= i; k++) {
				int mustpos = pos[k - 1];
				if (mustpos > i)
					continue;
				ll trash = (mustpos >= k ? sqr(ar[mustpos] - ar[k] + 1) : 0);
				dp[i][j] = min(dp[i][j], dp[mustpos][j - 1] + sqr(ar[i] - ar[k] + 1) - trash);
			}
		}
	}

	ll ans = inf;

	for (int i = 1; i <= lim; i++)
		ans = min(ans, dp[sz][i]);

	return ans;
}

• Subtask 1: 4 / 4
• Subtask 2: 12 / 12
• Subtask 3: 9 / 9
• Subtask 4: 0 / 16
• Subtask 5: 0 / 19
• Subtask 6: 0 / 40