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답안 #794861

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
794861 2023-07-27T01:47:05 Z PurpleCrayon Designated Cities (JOI19_designated_cities) C++17
23 / 100
 2000 ms 33656 KB 
#include <bits/stdc++.h>
using namespace std;

#define sz(v) int(v.size())
#define ar array
typedef long long ll;
const int N = 2e5+10, MOD = 1e9+7;
const ll INF = 1e18+10;

int n;
vector<ar<int, 3>> adj[N];
ll ans[N];

ll calc_one(int c, int p) {
    ll sum = 0;
    for (auto [nxt, w, _] : adj[c]) if (nxt != p) {
        sum += w + calc_one(nxt, c);
    }
    return sum;
}

void dfs1(int c, int p, ll x) {
    ans[1] = min(ans[1], x);
    for (auto [nxt, a, b] : adj[c]) if (nxt != p) {
        dfs1(nxt, c, x - a + b);
    }
}

int sub[N];
bool blocked[N];

int dfs_sub(int c, int p) {
    sub[c] = 1;
    for (auto [nxt, x, y] : adj[c]) if (nxt != p && !blocked[nxt]) {
        sub[c] += dfs_sub(nxt, c);
    }

    return sub[c];
}

int dfs_cent(int c, int p, int cnt) {
    for (auto [nxt, x, y] : adj[c]) if (nxt != p && !blocked[nxt] && sub[nxt] > cnt / 2)
        return dfs_cent(nxt, c, cnt);

    return c;
}

pair<ll, int> dfs_best(int c, int p, ll x) {
    pair<ll, int> best{x, c};
    for (auto [nxt, w, _] : adj[c]) if (!blocked[nxt] && nxt != p) {
        best = max(best, dfs_best(nxt, c, x + w));
    }

    return best;
}

vector<int> roots;
int process(int c) {
    roots.push_back(c); // can't hurt, and probably useful

    ll best_w = -1;
    int best_nxt = -1, best_c = -1;

    for (auto [nxt, w, _] : adj[c]) if (!blocked[nxt]) {
        auto cur = dfs_best(nxt, c, w);
        if (cur.first > best_w) {
            best_w = cur.first;
            best_nxt = nxt;
            best_c = cur.second;
        }
    }

    if (best_c != -1) {
        roots.push_back(best_c);
    }
    return best_nxt;
}

void build(int c) {
    if (c == -1) return;
    int cnt = dfs_sub(c, -1);
    int cent = dfs_cent(c, -1, cnt);

    int nxt = process(cent);
    blocked[cent] = 1;
    build(nxt);
}


int par[N], par_w[N], st[N], en[N], et[N], tt;
ll sum[N];
bool marked[N];

ll lzy[4 * N];
pair<ll, int> t[4 * N];

void build(int v, int tl, int tr) {
    lzy[v] = 0;
    if (tl == tr) t[v] = {sum[tl], tl};
    else {
        int tm = (tl + tr) / 2;
        build(2*v, tl, tm), build(2*v+1, tm+1, tr);
        t[v] = max(t[2*v], t[2*v+1]);
    }
}

void push(int v, int tl, int tr, ll x) {
    if (!x) return;
    t[v].first += x;
    if (tl != tr)
        lzy[2*v] += x, lzy[2*v+1] += x;
}

void app(int v, int tl, int tr) {
    push(v, tl, tr, lzy[v]);
    lzy[v] = 0;
}

void upd(int v, int tl, int tr, int l, int r, ll x) {
    app(v, tl, tr);
    if (r < tl || l > tr) return;
    if (l <= tl && tr <= r) {
        push(v, tl, tr, x);
        return;
    }

    int tm = (tl + tr) / 2;
    upd(2*v, tl, tm, l, r, x), upd(2*v+1, tm+1, tr, l, r, x);
    t[v] = max(t[2*v], t[2*v+1]);
}

pair<ll, int> qry(int v, int tl, int tr, int l, int r) {
    app(v, tl, tr);
    if (r < tl || l > tr) return {-INF, -1};
    if (l <= tl && tr <= r) return t[v];
    int tm = (tl + tr) / 2;
    return max(qry(2*v, tl, tm, l, r), qry(2*v+1, tm+1, tr, l, r));
}


void dfs_root(int c, int p) {
    par[c] = p;
    et[st[c] = tt++] = c;
    for (auto [nxt, w, _] : adj[c]) if (nxt != p) {
        par_w[nxt] = w;
        dfs_root(nxt, c);
    }
    en[c] = tt-1;
}

void add(int root) {
    tt = 0;
    memset(par, -1, sizeof(par));
    memset(sum, 0, sizeof(sum));
    memset(par_w, 0, sizeof(par_w));

    dfs_root(root, -1);
    for (int i = 1; i < n; i++) {
        int c = et[i];
        sum[i] = sum[st[par[c]]] + par_w[c];
    }

    memset(marked, 0, sizeof(marked));
    ll cur = accumulate(par_w, par_w + n, 0LL);
    build(1, 0, n-1);
    for (int i = 1; i <= n; i++) {
        /*
        pair<ll, int> best{-1, -1};
        for (int c = 0; c < n; c++) best = max(best, {sum[c], c});
        */
        pair<ll, int> best = qry(1, 0, n-1, 0, n-1);

        int c = et[best.second];
        while (c != -1 && !marked[c]) {
            marked[c] = 1;
            upd(1, 0, n-1, st[c], en[c],  -par_w[c]);
            // for (int j = st[c]; j <= en[c]; j++) sum[j] -= par_w[c];
            cur -= par_w[c];
            c = par[c];
        }

        ans[i+1] = min(ans[i+1], cur);
    }
}

void solve() {
    cin >> n;
    for (int i = 0; i < n-1; i++) {
        int a, b; cin >> a >> b, --a, --b;
        int x, y; cin >> x >> y;
        adj[a].push_back({b, x, y});
        adj[b].push_back({a, y, x});
    }

    fill(ans, ans + n, INF);
    dfs1(0, -1, calc_one(0, -1));

    build(0);
    for (int c : roots) add(c);

    int q; cin >> q;
    while (q--) {
        int x; cin >> x;
        cout << ans[x] << '\n';
    }
}

int main() {
    ios::sync_with_stdio(false); cin.tie(0);
    int T = 1;
    // cin >> T;
    while (T--) solve();
}

Subtask #1
6.0 / 6.0

# 결과 실행 시간 메모리 Grader output
1 Correct 4 ms 8276 KB Output is correct
2 Correct 4 ms 8276 KB Output is correct
3 Correct 4 ms 8300 KB Output is correct
4 Correct 4 ms 8276 KB Output is correct
5 Correct 4 ms 8276 KB Output is correct
6 Correct 4 ms 8276 KB Output is correct
7 Correct 4 ms 8276 KB Output is correct
8 Correct 4 ms 8276 KB Output is correct
9 Correct 4 ms 8276 KB Output is correct
10 Correct 4 ms 8276 KB Output is correct
11 Correct 4 ms 8276 KB Output is correct

Subtask #2
0 / 7.0

# 결과 실행 시간 메모리 Grader output
1 Correct 4 ms 8276 KB Output is correct
2 Execution timed out 2083 ms 33608 KB Time limit exceeded
3 Halted 0 ms 0 KB -

Subtask #3
0 / 9.0

# 결과 실행 시간 메모리 Grader output
1 Correct 4 ms 8276 KB Output is correct
2 Execution timed out 2076 ms 33656 KB Time limit exceeded
3 Halted 0 ms 0 KB -

Subtask #4
17.0 / 17.0

# 결과 실행 시간 메모리 Grader output
1 Correct 4 ms 8276 KB Output is correct
2 Correct 4 ms 8276 KB Output is correct
3 Correct 4 ms 8300 KB Output is correct
4 Correct 4 ms 8276 KB Output is correct
5 Correct 4 ms 8276 KB Output is correct
6 Correct 4 ms 8276 KB Output is correct
7 Correct 4 ms 8276 KB Output is correct
8 Correct 4 ms 8276 KB Output is correct
9 Correct 4 ms 8276 KB Output is correct
10 Correct 4 ms 8276 KB Output is correct
11 Correct 4 ms 8276 KB Output is correct
12 Correct 5 ms 8276 KB Output is correct
13 Correct 15 ms 8684 KB Output is correct
14 Correct 14 ms 8752 KB Output is correct
15 Correct 16 ms 8688 KB Output is correct
16 Correct 18 ms 8684 KB Output is correct
17 Correct 13 ms 8684 KB Output is correct
18 Correct 17 ms 8688 KB Output is correct
19 Correct 14 ms 8788 KB Output is correct
20 Correct 11 ms 8628 KB Output is correct
21 Correct 16 ms 8660 KB Output is correct
22 Correct 17 ms 8660 KB Output is correct
23 Correct 9 ms 8660 KB Output is correct
24 Correct 8 ms 8688 KB Output is correct
25 Correct 18 ms 8756 KB Output is correct
26 Correct 7 ms 8640 KB Output is correct

Subtask #5
0 / 17.0

# 결과 실행 시간 메모리 Grader output
1 Correct 4 ms 8276 KB Output is correct
2 Execution timed out 2083 ms 33608 KB Time limit exceeded
3 Halted 0 ms 0 KB -

Subtask #6
0 / 44.0

# 결과 실행 시간 메모리 Grader output
1 Correct 4 ms 8276 KB Output is correct
2 Correct 4 ms 8276 KB Output is correct
3 Correct 4 ms 8300 KB Output is correct
4 Correct 4 ms 8276 KB Output is correct
5 Correct 4 ms 8276 KB Output is correct
6 Correct 4 ms 8276 KB Output is correct
7 Correct 4 ms 8276 KB Output is correct
8 Correct 4 ms 8276 KB Output is correct
9 Correct 4 ms 8276 KB Output is correct
10 Correct 4 ms 8276 KB Output is correct
11 Correct 4 ms 8276 KB Output is correct
12 Correct 4 ms 8276 KB Output is correct
13 Execution timed out 2083 ms 33608 KB Time limit exceeded
14 Halted 0 ms 0 KB -