#include<bits/stdc++.h>
#include<fstream>
using namespace std;
#define ll long long
#define pb push_back
#define forr(i, a, b) for(int i = a; i < b; i++)
#define dorr(i, a, b) for(int i = a; i >= b; i--)
#define ld long double
#define vt vector
#include<fstream>
#define fi first
#define se second
#define pll pair<ll, ll>
#define pii pair<int, int>
const ld PI = 3.14159265359;
const ll mod = 1e9 + 7;
const int mxn = 2e5 + 5, mxm = 1e5, sq = 400;
const ld inf = 1e9;
int n, r, q, root;
int colour[mxn + 1], tin[mxn + 1], tout[mxn + 1], tt = 0, cnt[mxn + 1];
vt<int>vec[mxn + 1], adj[mxn + 1], to[mxn + 1];
vt<ll>ansb[mxn + 1];
void dfs(int s, int pre){
tin[s] = ++tt;
for(auto i: adj[s]){
if(i != pre){
dfs(i, s);
}
}
tout[s] = tt;
}
struct th{
int id, pos, type;
bool operator <(const th &b){
if(pos != b.pos)return(pos < b.pos);
if(type != b.type)return(type < b.type);
if(id != b.id)return(id > b.id);
}
};
void solvebig(int i){
vt<th>comp;
for(auto k: vec[i]){
comp.pb({0, tin[k], -1}); comp.pb({0, tout[k],1});
}
for(int j = 1; j <= r; j++){
if(j != i){
for(auto k: vec[j]){
comp.pb({k, tin[k], -1}); comp.pb({k, tout[k], 1});
}
}
}
sort(comp.begin(), comp.end());
ll cnt =0 ;
for(auto [id, pos, type]: comp){
if(id == 0){
if(type == 1)cnt++;
else cnt--;
}else{
if(type == 1)ansb[i][id] -= cnt;
else ansb[i][id] += cnt;
}
}
}
signed main(){
ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0);
cin >> n >> r >> q;
cin >> colour[1];
vec[colour[1]].pb(1);
for(int i = 2; i <= n; i++){
int p;
cin >> p >> colour[i]; cnt[colour[i]]++;
vec[colour[i]].pb(i); adj[p].pb(i);
}
dfs(1, -1);
for(int i = 1; i <= r; i++){
for(auto j: vec[i]){
to[i].pb(tin[j]);
}
sort(to[i].begin(), to[i].end());
}
for(int i = 1; i <= r; i++){
if(cnt[i] >= sq){
ansb[i].resize(r + 1);
solvebig(i);
}
}
while(q--){
int r1, r2; cin >> r1 >> r2;
if(cnt[r1] >= sq){
cout << ansb[r1][r2] << "\n";
}else{
ll ans = 0;
for(auto i: vec[r1]){
int idl = lower_bound(to[r2].begin(), to[r2].end(), tin[i]) - to[r2].begin();
int idr = upper_bound(to[r2].begin(), to[r2].end(), tout[i]) - to[r2].begin() - 1;
ans += 1LL * (idr - idl + 1);
}
cout << ans << "\n";
}
}
return(0);
}
