제출 #793682

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
793682		arush_agu	은행 (IZhO14_bank)	C++17	71 / 100	1068 ms	19184 KiB

bank

#include <algorithm>
#include <cctype>
#include <cmath>
#include <cstdio>
#include <cstring>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#include <functional>
#include <iomanip>
#include <iostream>
#include <iterator>
#include <list>
#include <map>
#include <numeric>
#include <queue>
#include <random>
#include <set>
#include <sstream>
#include <stack>
#include <string>
#include <unordered_map>
#include <unordered_set>
#include <vector>

#ifdef DEBUG
#include <time.h>
#endif

#define all(a) (a).begin(), (a).end()
#define rev(a) (a).rbegin(), (a).rend()
#define F first
#define S second
int recur_depth = 0;
#ifdef DEBUG
#define dbg(x)                                                                 \
  {                                                                            \
    ++recur_depth;                                                             \
    auto x_ = x;                                                               \
    --recur_depth;                                                             \
    cerr << string(recur_depth, '\t') << "\e[91m" << __func__ << ":"           \
         << __LINE__ << "\t" << #x << " = " << x_ << "\e[39m" << endl;         \
  }
#else
#define dbg(x)
#endif

using namespace std;
using namespace __gnu_pbds;

typedef pair<int, int> ii;

typedef long long ll;
typedef long double ld;
typedef pair<ll, ll> llll;

typedef vector<int> vi;
typedef vector<vi> vvi;
typedef vector<pair<int, int>> vii;
typedef vector<vii> vvii;

typedef vector<ll> vl;
typedef vector<vl> vvl;
typedef vector<pair<ll, ll>> vll;
typedef vector<vll> vvll;

typedef vector<bool> vb;

template <class type1>
using ordered_set = tree<type1, null_type, less<type1>, rb_tree_tag,
                         tree_order_statistics_node_update>;

template <typename A, typename B>
ostream &operator<<(ostream &os, const pair<A, B> &p) {
  return os << '(' << p.first << ", " << p.second << ')';
}
template <typename T_container, typename T = typename enable_if<
                                    !is_same<T_container, string>::value,
                                    typename T_container::value_type>::type>
ostream &operator<<(ostream &os, const T_container &v) {
  os << '{';
  string sep;
  for (const T &x : v)
    os << sep << x, sep = ", ";
  return os << '}';
}

const ll MOD = 1e9 + 7;
// const ll MOD = 998244353;
const ll INF = 1e9;
const ld EPS = 1e-9;

void solve() {
  int n, m;
  cin >> n >> m;
  vi a(n);
  for (int &x : a)
    cin >> x;
  vi b(m);
  for (int &x : b)
    cin >> x;

  sort(all(a)), sort(all(b));

  vector<string> anss = {"NO", "YES"};

  vvi sum_msks(1001 * m);
  for (int i = 0; i < (1 << m); i++) {
    int s = 0;
    for (int j = 0; j < m; j++)
      if ((1 << j) & i)
        s += b[j];
    sum_msks[s].push_back(i);
  }

  if (n == 1) {
    cout << anss[!sum_msks[a[0]].empty()] << '\n';
    return;
  }

  vvi dp(n, vi(1 << m));
  for (int msk = 0; msk < (1 << m); msk++)
    for (int sub_msk : sum_msks[a.back()])
      if (__builtin_popcount(msk & sub_msk) == __builtin_popcount(sub_msk))
        dp[n - 1][msk] = 1;

  for (int i = n - 2; i >= 0; i--)
    for (int msk = 0; msk < (1 << m); msk++)
      for (int sub_msk : sum_msks[a[i]])
        if (__builtin_popcount(msk & sub_msk) == __builtin_popcount(sub_msk))
          dp[i][msk] |= dp[i + 1][msk ^ sub_msk];

  cout << anss[dp[0][(1 << m) - 1]] << "\n";
}

int main() {
  ios_base::sync_with_stdio(0);
  cin.tie(NULL);

  clock_t start = clock();

  int test_cases = 1;
  // cin >> test_cases;

  while (test_cases--)
    solve();

#ifdef DEBUG
  cerr << fixed << setprecision(10)
       << "\nTime Taken: " << (double)(clock() - start) / CLOCKS_PER_SEC
       << "s\n";
#endif
  return 0;
}

컴파일 시 표준 에러 (stderr) 메시지

bank.cpp: In function 'int main()':
bank.cpp:139:11: warning: unused variable 'start' [-Wunused-variable]
  139 |   clock_t start = clock();
      |           ^~~~~

• Subtask 1: 19 / 19
• Subtask 2: 25 / 25
• Subtask 3: 27 / 27
• Subtask 4: 0 / 29