oj.uz

답안 #792731

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
792731 2023-07-25T08:23:04 Z 박상훈(#10052) Line Town (CCO23_day1problem3) C++17
7 / 25
 731 ms 24076 KB 
#include <bits/stdc++.h>

using namespace std;
typedef long long ll;

constexpr ll INF = 4e18;

struct Seg{
	int tree[2002000];
	int sz;

	void init(int n){
		sz = n;
		fill(tree, tree+sz*2, 0);
	}

	void update(int p, ll x){
		p += sz;
		tree[p] = x;
		for (p>>=1;p;p>>=1) tree[p] = tree[p<<1] + tree[p<<1|1];
	}

	int query(int l, int r){
		++r;
		int ret = 0;
		for (l+=sz, r+=sz;l<r;l>>=1, r>>=1){
			if (l&1) ret += tree[l++];
			if (r&1) ret += tree[--r];
		}

		return ret;
	}
}tree, tree2;

int a[500500], I[500500];
ll dp[2][500500];

int cnt2[2], col_b[500500], col_f[500500], col[500500];

int f(int s, int e, int val){
	if ((e-s)%2 == 0) return val;
	return -val;
}

int main(){
	int n;
	scanf("%d", &n);
	for (int i=1;i<=n;i++) scanf("%d", a+i);

	for (int i=1;i<=n;i++){
		if (f(i, 0, a[i]) == -abs(a[i])) col[i] = 0;
		else col[i] = 1;
	}

	for (int i=1;i<=n;i++) I[i] = i;
	sort(I+1, I+n+1, [&](int i, int j){return abs(a[i]) < abs(a[j]);});
	tree.init(n+1);
	tree2.init(n+1);

	for (int i=1,r;i<=n;i=r+1){
		r = i;
		while(r+1<=n && abs(a[I[i]]) == abs(a[I[r+1]])) r++;

		for (int t=i;t<=r;t++) tree.update(I[t], 1);
		for (int t=i;t<=r;t++) tree2.update(I[t], 1);

		for (int z=0;z<2;z++){
			int len = r;
			int cnt = r-i+1;
			dp[z][len] = INF;

			for (int s=0;s<2;s++){

				// init here
				vector<int> V[2], V2[2];
				cnt2[0] = cnt2[1] = 0;

				for (int t=i;t<=r;t++){
					int idx = I[t];

					V[col[idx]].push_back(tree.query(1, idx));
					V2[col[idx]].push_back(tree2.query(1, idx));
				}

				sort(V[0].begin(), V[0].end());
				sort(V[1].begin(), V[1].end());


				col_f[0] = z^1;
				for (int i=1;i<=cnt;i++){
					col_f[i] = col_f[i-1] ^ 1;
					if (i<=s) cnt2[col_f[i]]++; 
				}

				col_b[len] = ((z+len-1)&1) ^ 1;
				if (len >= len-(cnt-s)+1) cnt2[col_b[len]]++;
				for (int i=len-1;i>=len-(cnt-s)+1;i--){
					col_b[i] = col_b[i+1] ^ 1;
					cnt2[col_b[i]]++;
				}

				// printf("\ni = %d, z = %d, s = %d -> cnt = (%d, %d) / sz = (%d, %d)\n", i, z, s, cnt2[0], cnt2[1], (int)V[0].size(), (int)V[1].size());

				if (cnt2[0]!=(int)V[0].size() || cnt2[1]!=(int)V[1].size()) continue;

				int cp[2] = {col_f[s+1], col_f[s+2]};
				int cq[2] = {col_b[len - (cnt-s) + 1], col_b[len - (cnt-s) + 2]};

				int pp[2] = {0, 0}, pq[2] = {0, 0};
				if (s==1) {
					pp[1] = 1;
					if (cq[0]==z) pq[0]++;
					else pq[1]++;
				}

				ll cst = 0, cst2 = 0;
				cnt2[0] = cnt2[1] = 0;
				for (int i=1;i<=s;i++){
					cst += abs(V[col_f[i]][cnt2[col_f[i]]] - i);
					cst2 += abs(V2[col_f[i]][cnt2[col_f[i]]] - i);
					
					cnt2[col_f[i]]++;
				} 

				for (int i=len-(cnt-s)+1;i<=len;i++){
					cst += abs(V[col_b[i]][cnt2[col_b[i]]] - i);
					cst2 += abs(V2[col_b[i]][cnt2[col_b[i]]] - (i-len+cnt));
					
					cnt2[col_b[i]]++;
				}

				int nz = z ^ s;

				// printf("i = %d, z = %d, s = %d -> cst = %lld\n", i, z, s, cst);


				for (int k=s;k<=cnt;k+=2){
					dp[z][len] = min(dp[z][len], dp[nz][i-1] + cst - cst2 / 2);
					if (k+2 > cnt) break;

					cst -= abs(V[cq[0]][pq[0]] - (len - (cnt-k) + 1));
					cst -= abs(V[cq[1]][pq[1]] - (len - (cnt-k) + 2));

					cst2 -= abs(V2[cq[0]][pq[0]] - (k+1));
					cst2 -= abs(V2[cq[1]][pq[1]] - (k+2));

					pq[0]++, pq[1]++;

					cst += abs(V[cp[0]][pp[0]] - (k+1));
					cst += abs(V[cp[1]][pp[1]] - (k+2));

					cst2 += abs(V2[cp[0]][pp[0]] - (k+1));
					cst2 += abs(V2[cp[1]][pp[1]] - (k+2));

					pp[0]++, pp[1]++;
				}
			}

			// printf("%d %d -> %lld\n", i, z, dp[z][i]);
		}

		for (int t=i;t<=r;t++) tree2.update(I[t], 0);


		// assert(i==r);

		// // abs distinct
		// int pos = I[i];
		// for (int z=0;z<2;z++){
		// 	dp[z][i] = INF;

		// 	if (f(pos, z, a[pos]) == -abs(a[pos])) dp[z][i] = min(dp[z][i], dp[z^1][i-1] + tree.query(1, pos-1));
		// 	if (f(pos, z+i-1, a[pos]) == abs(a[pos])) dp[z][i] = min(dp[z][i], dp[z][i-1] + tree.query(pos+1, n));

		// 	if (i==1) dp[z][i] = 0;

		// 	// printf("%d %d -> %lld\n", z, i, dp[z][i]);
		// }

		// tree.update(pos, 1);
	}

	if (dp[1][n]==INF) printf("-1\n");
	else printf("%lld\n", dp[1][n]);
}

Compilation message

Main.cpp: In function 'int main()':
Main.cpp:47:7: warning: ignoring return value of 'int scanf(const char*, ...)' declared with attribute 'warn_unused_result' [-Wunused-result]
   47 |  scanf("%d", &n);
      |  ~~~~~^~~~~~~~~~
Main.cpp:48:30: warning: ignoring return value of 'int scanf(const char*, ...)' declared with attribute 'warn_unused_result' [-Wunused-result]
   48 |  for (int i=1;i<=n;i++) scanf("%d", a+i);
      |                         ~~~~~^~~~~~~~~~~

Subtask #1
0 / 3.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 340 KB Output is correct
2 Correct 0 ms 340 KB Output is correct
3 Correct 1 ms 340 KB Output is correct
4 Incorrect 2 ms 468 KB Output isn't correct
5 Halted 0 ms 0 KB -

Subtask #2
0 / 3.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 340 KB Output is correct
2 Correct 0 ms 340 KB Output is correct
3 Correct 1 ms 340 KB Output is correct
4 Incorrect 2 ms 468 KB Output isn't correct
5 Halted 0 ms 0 KB -

Subtask #3
0 / 3.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 340 KB Output is correct
2 Correct 0 ms 340 KB Output is correct
3 Correct 1 ms 340 KB Output is correct
4 Incorrect 2 ms 468 KB Output isn't correct
5 Halted 0 ms 0 KB -

Subtask #4
0 / 4.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 340 KB Output is correct
2 Correct 0 ms 340 KB Output is correct
3 Correct 1 ms 340 KB Output is correct
4 Incorrect 2 ms 468 KB Output isn't correct
5 Halted 0 ms 0 KB -

Subtask #5
4.0 / 4.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 340 KB Output is correct
2 Correct 0 ms 340 KB Output is correct
3 Correct 2 ms 468 KB Output is correct
4 Correct 2 ms 468 KB Output is correct
5 Correct 2 ms 340 KB Output is correct
6 Correct 2 ms 468 KB Output is correct
7 Correct 2 ms 468 KB Output is correct
8 Correct 2 ms 344 KB Output is correct
9 Correct 1 ms 340 KB Output is correct
10 Correct 0 ms 340 KB Output is correct
11 Correct 2 ms 468 KB Output is correct
12 Correct 2 ms 432 KB Output is correct
13 Correct 2 ms 340 KB Output is correct

Subtask #6
3.0 / 3.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 340 KB Output is correct
2 Correct 0 ms 340 KB Output is correct
3 Correct 2 ms 468 KB Output is correct
4 Correct 2 ms 468 KB Output is correct
5 Correct 2 ms 340 KB Output is correct
6 Correct 2 ms 468 KB Output is correct
7 Correct 2 ms 468 KB Output is correct
8 Correct 2 ms 344 KB Output is correct
9 Correct 1 ms 340 KB Output is correct
10 Correct 0 ms 340 KB Output is correct
11 Correct 2 ms 468 KB Output is correct
12 Correct 2 ms 432 KB Output is correct
13 Correct 2 ms 340 KB Output is correct
14 Correct 479 ms 23948 KB Output is correct
15 Correct 719 ms 23976 KB Output is correct
16 Correct 661 ms 23916 KB Output is correct
17 Correct 731 ms 23984 KB Output is correct
18 Correct 646 ms 23912 KB Output is correct
19 Correct 661 ms 23916 KB Output is correct
20 Correct 1 ms 340 KB Output is correct
21 Correct 0 ms 340 KB Output is correct
22 Correct 562 ms 23912 KB Output is correct
23 Correct 507 ms 24076 KB Output is correct
24 Correct 462 ms 23868 KB Output is correct

Subtask #7
0 / 2.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 340 KB Output is correct
2 Correct 0 ms 340 KB Output is correct
3 Correct 1 ms 340 KB Output is correct
4 Incorrect 2 ms 468 KB Output isn't correct
5 Halted 0 ms 0 KB -

Subtask #8
0 / 3.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 340 KB Output is correct
2 Correct 0 ms 340 KB Output is correct
3 Correct 1 ms 340 KB Output is correct
4 Incorrect 2 ms 468 KB Output isn't correct
5 Halted 0 ms 0 KB -