This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include<bits/stdc++.h>
using namespace std;
#define all(fl) fl.begin(),fl.end()
#define pb push_back
#define fi first
#define se second
#define for1(i,j,k) for(int i=j;i<=k;i++)
#define for2(i,j,k) for(int i=j;i>=k;i--)
#define for3(i,j,k,l) for(int i=j;i<=k;i+=l)
#define lb lower_bound
#define ub upper_bound
#define sz(a) (int)a.size()
#define pii pair<int,int>
#define pli pair<long long,int>
#define gcd __gcd
#define lcm(x,y) x*y/__gcd(x,y)
#define pil pair<int,long long>
#define pll pair<long long,long long>
long long a[3009];
map<int,int>type;
struct cus{
int u;
long long val;
bool operator < (const cus &p)const {
return val<p.val;
}
};
signed main(){
ios_base::sync_with_stdio(0);
cin.tie(0);
//freopen("temp.INP","r",stdin);
//freopen("temp.OUT","w",stdout);
int n,m,k;
cin>>n>>m>>k;
long long x,y,z,t;
cin>>x>>y>>z>>t;
for1(i,1,m){
cin>>a[i];
type[a[i]]=1;
}
priority_queue<cus>t1;
for1(i,1,m-1){
long long cost=(a[i]-1)*y;
if (cost>t)continue;
int last=a[i];
int lst=a[i];
long long tme=(t-cost);
tme/=x;
last+=tme;
//cout<<i<<" "<<last<<'\n';
for1(j,1,k-m){
int l=last+1,r=a[i+1]-1,nw=-1;
while (l<=r){
int mid=(l+r)/2;
//cerr<<mid<<'\n';
long long cc=1ll*(mid-a[i])*z+(a[i]-1)*y;
cc=max(cc,1ll*(mid-1-lst)*x+(lst-a[i])*z+(a[i]-1)*y);
if (cc<=t){
nw=mid;
l=mid+1;
}
else r=mid-1;
}
//cerr<<i<<" "<<nw<<" "<<last<<" "<<lst<<'\n';
//cout<<nw<<'\n';
//cout<<last<<'\n';
if (nw==-1)break;
lst=nw;
long long vcl=(a[i]-1)*y+(lst-a[i])*z;
tme=t-vcl;
tme/=x;
int len=a[i+1]-1-lst+1;
last=nw+tme;
t1.push({nw,min(tme+1,1ll*len)});
}
}
int vcl=k-m;
for1(i,1,vcl){
if (t1.empty())break;
int nw=t1.top().u;
t1.pop();
a[++m]=nw;
type[nw]=2;
//cout<<nw<<'\n';
}
sort(a+1,a+1+m);
int lst=1,ans=0;
for1(i,1,m){
if (type[a[i]]==1){
lst=a[i];
}
long long cost=(a[i]-lst)*z+(lst-1)*y;
if (cost<=t)ans++;
}
ans--;
lst=1;
//for1(i,1,m)cout<<a[i]<<'\n';
//cout<<m<<'\n';
for1(i,1,m-1){
if (type[a[i]]==1){
lst=a[i];
}
int l=a[i]+1,r=a[i+1]-1;
if (l>r)continue;
long long cost=(a[i]-lst)*z+(lst-1)*y;
if (cost>t)continue;
//cout<<a[i]<<" "<<a[i+1]<<" "<<cost<<'\n';
long long tme=t-cost;
tme/=x;
tme=min(tme,1ll+r-l);
ans+=tme;
}
cout<<ans;
}
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