제출 #789753

#제출 시각아이디문제언어결과실행 시간메모리
789753benjaminkleyn늑대인간 (IOI18_werewolf)C++17
100 / 100
607 ms107196 KiB
#include "werewolf.h" #include <bits/stdc++.h> using namespace std; typedef long long ll; int n; vector<int> g1[200000], g2[200000]; int par1[200000][20], par2[200000][20]; int e[200000]; int find(int u) { return e[u] == u ? u : e[u] = find(e[u]); } int euler1[200000]; int in1[200000] = {0}, out1[200000] = {0}, t1 = 0; int in2[200000] = {0}, out2[200000] = {0}, t2 = 0; vector<int> c1[200000], c2[200000]; void dfs1(const int &u) { euler1[in1[u] = t1++] = u; for (const int &v : c1[u]) dfs1(v); out1[u] = t1; } void dfs2(const int &u) { in2[u] = t2++; for (const int &v : c2[u]) dfs2(v); out2[u] = t2; } struct Event { int l, r, t, i; }; vector<Event> events[200000]; int t[200000] = {0}; void update(int idx) { for (; idx < n; idx |= (idx + 1)) t[idx]++; } int query(int idx) { int res = 0; for (; idx >= 0; idx = (idx & (idx + 1)) - 1) res += t[idx]; return res; } vector<int> check_validity(int N, vector<int> X, vector<int> Y, vector<int> S, vector<int> E, vector<int> L, vector<int> R) { n = N; int Q = S.size(), M = X.size(); vector<int> A(Q, 0); int K = 0; while ((1 << K) < N) K++; for (int i = 0; i < N; i++) par1[i][0] = par2[i][0] = i; for (int i = 0; i < M; i++) { if (X[i] < Y[i]) swap(X[i], Y[i]); g1[X[i]].push_back(Y[i]); g2[Y[i]].push_back(X[i]); } iota(e, e + N, 0); for (int u = 0; u < N; u++) for (int v : g1[u]) { v = find(v); e[v] = u; par1[v][0] = u; } iota(e, e + N, 0); for (int u = N - 1; u >= 0; u--) for (int v : g2[u]) { v = find(v); e[v] = u; par2[v][0] = u; } for (int k = 1; k <= K; k++) for (int u = 0; u < N; u++) { par1[u][k] = par1[par1[u][k-1]][k-1]; par2[u][k] = par2[par2[u][k-1]][k-1]; } for (int i = 0; i < N; i++) { if (par1[i][0] != i) c1[par1[i][0]].push_back(i); if (par2[i][0] != i) c2[par2[i][0]].push_back(i); } for (int i = N - 1; i >= 0; i--) if (!in1[i]) dfs1(i); for (int i = 0; i < N; i++) if (!in2[i]) dfs2(i); for (int i = 0; i < Q; i++) { for (int k = K; k >= 0; k--) { if (par1[E[i]][k] <= R[i]) E[i] = par1[E[i]][k]; if (par2[S[i]][k] >= L[i]) S[i] = par2[S[i]][k]; } events[in1[E[i]]-1].push_back({in2[S[i]], out2[S[i]]-1, -1, i}); events[out1[E[i]]-1].push_back({in2[S[i]], out2[S[i]]-1, 1, i}); } for (int idx = 0; idx < N; idx++) { update(in2[euler1[idx]]); for (auto &[l, r, t, i] : events[idx]) A[i] += t * (query(r) - query(l - 1)); } for (int &x : A) x = (x > 0); return A; }
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