제출 #789752

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
789752		benjaminkleyn	늑대인간 (IOI18_werewolf)	C++17	100 / 100	511 ms	96940 KiB

werewolf

#include "werewolf.h"
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;

vector<int> g[200000];

int par1[200000][20], par2[200000][20];
int e[200000];
int find(int u)
{
    return e[u] == u ? u : e[u] = find(e[u]);
}

int euler1[200000];
int in1[200000] = {0}, out1[200000] = {0}, t1 = 0;
int in2[200000] = {0}, out2[200000] = {0}, t2 = 0;
vector<int> c1[200000], c2[200000];
void dfs1(int u)
{
    in1[u] = t1++;
    euler1[in1[u]] = u;
    for (int v : c1[u])
        dfs1(v);
    out1[u] = t1;
}
void dfs2(int u)
{
    in2[u] = t2++;
    for (int v : c2[u])
        dfs2(v);
    out2[u] = t2;
}

struct Event
{
    int l, r, t, i;
};
vector<Event> events[200000];

int t[200000] = {0};
void update(int N, int idx, int val)
{
    for (; idx < N; idx |= (idx + 1))
        t[idx] += val;
}
int quer(int r)
{
    int res = 0;
    for (; r >= 0; r = (r & (r + 1)) - 1)
        res += t[r];
    return res;
}
int query(int l, int r)
{
    return quer(r) - quer(l - 1);
}

vector<int> check_validity(int N, vector<int> X, vector<int> Y, vector<int> S, vector<int> E, vector<int> L, vector<int> R)
{
    int Q = S.size(), M = X.size();
    vector<int> A(Q, 0);
    int K = 0;
    while ((1 << K) < N) K++;

    for (int i = 0; i < N; i++)
        par1[i][0] = par2[i][0] = i;

    for (int i = 0; i < M; i++)
    {
        g[X[i]].push_back(Y[i]);
        g[Y[i]].push_back(X[i]);
    }

    iota(e, e + N, 0);

    for (int u = 0; u < N; u++)
        for (int v : g[u])
            if (v < u)
            {
                v = find(v);
                e[v] = u;
                par1[v][0] = u;
            }

    iota(e, e + N, 0);

    for (int u = N - 1; u >= 0; u--)
        for (int v : g[u])
            if (v > u)
            {
                v = find(v);
                e[v] = u;
                par2[v][0] = u;
            }

    for (int k = 1; k <= K; k++)
        for (int u = 0; u < N; u++)
        {
            par1[u][k] = par1[par1[u][k-1]][k-1];
            par2[u][k] = par2[par2[u][k-1]][k-1];
        }

    for (int i = 0; i < N; i++)
    {
        if (par1[i][0] != i)
            c1[par1[i][0]].push_back(i);
        if (par2[i][0] != i)
            c2[par2[i][0]].push_back(i);
    }

    for (int i = N - 1; i >= 0; i--)
        if (!in1[i])
            dfs1(i);

    for (int i = 0; i < N; i++)
        if (!in2[i])
            dfs2(i);

    for (int i = 0; i < Q; i++)
    {
        for (int k = K; k >= 0; k--)
        {
            if (par1[E[i]][k] <= R[i])
                E[i] = par1[E[i]][k];
            if (par2[S[i]][k] >= L[i])
                S[i] = par2[S[i]][k];
        }
        events[in1[E[i]]-1].push_back({in2[S[i]], out2[S[i]]-1, -1, i});
        events[out1[E[i]]-1].push_back({in2[S[i]], out2[S[i]]-1, 1, i});
    }

    for (int idx = 0; idx < N; idx++)
    {
        update(N, in2[euler1[idx]], 1);
        for (auto &[l, r, t, i] : events[idx])
            A[i] += t * query(l, r);
    }
    for (int &x : A)
        x = (x > 0);

    return A;
}

• Subtask 1: 7 / 7
• Subtask 2: 8 / 8
• Subtask 3: 34 / 34
• Subtask 4: 51 / 51