이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
//0 1 1 0 1
//0 1 0 0 1
//1 0 0 1 1
//0 1 1 0 1
#include <bits/stdc++.h>
#pragma GCC optimize("Ofast,unroll-loops")
// #pragma GCC target("avx2")
using namespace std;
#define F first
#define S second
#define pb push_back
#define sze size()
#define all(x) x.begin() , x.end()
#define wall__ cout << "--------------------------------------\n";
#define kids int mid = (tl + tr) >> 1, cl = v << 1, cr = v << 1 | 1
#define file_io freopen("input.cpp", "r", stdin); freopen("output.cpp", "w", stdout);
typedef long long ll;
typedef long double dl;
typedef pair < int , int > pii;
typedef pair < int , ll > pil;
typedef pair < ll , int > pli;
typedef pair < ll , ll > pll;
typedef pair < int , pii > piii;
typedef pair < ll, pll > plll;
const ll N = 2000 + 10, M = N * 100;
const ll mod = 1e9 + 7;
const ll inf = 2e16;
const ll INF = 1e9 + 10;
const ll lg = 32;
ll dp[M + M], c1[N], c2[N], v1[N], v2[N], f1[N], f2[N];
int n, m;
void solve () {
cin >> n;
for (int i = 1; i <= n; i++) {
cin >> c1[i] >> v1[i] >> f1[i];
}
cin >> m;
for (int i = 1; i <= m; i++) {
cin >> c2[i] >> v2[i] >> f2[i];
}
for (int i = M + 1; i < M + M; ++i) dp[i] = -inf;
for (int i = 1; i <= n; i++) {
for (int j = i * 50; j >= 0; --j) {
dp[j + M] = max(dp[j + M], dp[j - c1[i] + M] - v1[i]);
}
}
for (int i = 1; i <= m; i++) {
for (int j = i * -50; j <= n * 50; j++) {
dp[j + M] = max(dp[j + M], dp[j + c2[i] + M] + v2[i]);
}
}
cout << dp[0 + M] << '\n';
}
int main() {
ios::sync_with_stdio(0); cin.tie(0); cout.tie(0);
int t = 1;
// cin >> t;
while (t--) {solve();}
return 0;
}
/*
*/
//shrek is love;
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