Submission #789091

#TimeUsernameProblemLanguageResultExecution timeMemory
789091ono_de206Advertisement 2 (JOI23_ho_t2)C++14
0 / 100
1 ms316 KiB
#include<bits/stdc++.h> using namespace std; #define fast ios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0); #define in insert #define all(x) x.begin(),x.end() #define pb push_back #define eb emplace_back #define ff first #define ss second #define int long long typedef long long ll; typedef vector<int> vi; typedef set<int> si; typedef multiset<int> msi; typedef pair<int, int> pii; typedef vector<pii> vpii; typedef pair<int, int> P; template<typename T, typename U> ostream & operator << (ostream &out, const pair<T, U> &c) { out << c.first << ' ' << c.second; return out; } template<typename T> ostream & operator << (ostream &out, vector<T> &v) { const int sz = v.size(); for (int i = 0; i < sz; i++) { if (i) out << ' '; out << v[i]; } return out; } template<typename T> istream & operator >> (istream &in, vector<T> &v) { for (T &x : v) in >> x; return in; } template<typename T, typename U> istream & operator >> (istream &in, pair<T, U> &c) { in >> c.first; in >> c.second; return in; } template<typename T> void mxx(T &a, T b){if(b > a) a = b;} template<typename T> void mnn(T &a, T b){if(b < a) a = b;} const int mxn = 5e5 + 10, inf = 1e18 + 10; void go() { int n; cin >> n; vector<pair<int, int>> a(n); for(int i = 0; i < n; i++) { cin >> a[i].ff >> a[i].ss; } sort(all(a)); a.erase(unique(all(a)), a.end()); n = a.size(); int ans1 = 0, ans2 = 0; vector<pair<int, int>> v; for(int i = 0; i < n; i++) { v.eb(a[i].ff - a[i].ss, a[i].ff); } sort(all(v)); reverse(all(v)); int ls = -inf; for(int i = 0; i < n; i++) { if(v[i].ss > ls) { ans1++; ls = v[i].ss; } } v.clear(); for(int i = 0; i < n; i++) { v.eb(-a[i].ff - a[i].ss, a[i].ff); } sort(all(v), [&](pair<int, int> a, pair<int, int> b) { if(a.ff == b.ff) return a.ss < b.ss; else return a.ff > b.ff; }); ls = inf; for(int i = 0; i < n; i++) { if(v[i].ss < ls) { ans2++; ls = v[i].ss; } } // cout << ans1 << ' ' << ans2 << '\n'; cout << max(ans1, ans2) << '\n'; } signed main() { fast; int t = 1; // cin >> t; while(t--) { go(); } return 0; }
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