이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <iostream>
#include <bits/stdc++.h>
using namespace std;
#define lli long long int
#define debug(a) cout << #a << " = " << a << endl
#define debugsl(a) cout << #a << " = " << a << ", "
#define rep(i,a,b) for(int i = (a); i <= (b); i++)
#define repa(i,a,b) for(int i = (a); i >= (b); i--)
#define pll pair<lli,lli>
#define MAX 1000000
lli m,l,res,ceros,a,b,c;
lli arr[2][102];
lli dp[2][MAX+2], usados[MAX+2], existe[2][MAX+2];
int main()
{
ios_base::sync_with_stdio(false);
cin.tie(NULL);
cin >> m >> l;
repa(i,m,1) cin >> arr[0][i];
cin >> ceros;
rep(i,1,m) cin >> arr[1][i];
rep(id,0,1) {
existe[id][0] = true;
rep(i,1,m) {
rep(j,1,MAX) {
a = j-i;
usados[j] = 0;
if(a < 0) continue;
if (!existe[id][a]) continue;
if (usados[a] == arr[id][i]) continue; //podrai hacer un berak? segun yo no
b = dp[id][a]+1;
if (b > dp[id][j]) {
existe[id][j] = 1;
usados[j] = usados[a]+1;
dp[id][j] = b;
}
}
}
}
//rep(id,0,1) {
// debug(id);
// rep(i,0,15) {
// debugsl(i);
// debugsl(existe[id][i]);
// debug(dp[id][i]);
// }
//}
res = -1;
a = 0;
b = 0;
if (l < 0) a = -l;
else b = l;
rep(i,0,MAX) {
if( (a+i) > MAX || (b+i) > MAX) break;
if(!existe[0][i+a] || !existe[1][i+b]) continue;
c = dp[0][i+a] + dp[1][i+b];
res = max(res,c);
}
if(res == -1) {
cout << "impossible";
return 0;
}
res += ceros;
if(res == 0) cout << "impossible";
else cout << res;
return 0;
}
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