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답안 #787532

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
787532 2023-07-19T09:15:42 Z 반딧불(#10031) 함박 스테이크 (JOI20_hamburg) C++17
15 / 100
 281 ms 11532 KB 
#include <bits/stdc++.h>

using namespace std;

typedef long long ll;

void input();
bool check1();
bool check2();
bool check3();
bool check4();
void output();

int main(){
    input();
    if(!check1()) if(!check2()) if(!check3()) check4();
    output();
}

int n, k;
vector<int> xCoord(1), yCoord(1);
int L[200002], R[200002], D[200002], U[200002], X, Y;
vector<pair<int, int> > ans;

void input(){
    scanf("%d %d", &n, &k);
    for(int i=1; i<=n; i++){
        scanf("%d %d %d %d", &L[i], &D[i], &R[i], &U[i]);
        xCoord.push_back(L[i]); xCoord.push_back(R[i]);
        yCoord.push_back(D[i]); yCoord.push_back(U[i]);
    }
    sort(xCoord.begin(), xCoord.end()); xCoord.erase(unique(xCoord.begin(), xCoord.end()), xCoord.end());
    sort(yCoord.begin(), yCoord.end()); yCoord.erase(unique(yCoord.begin(), yCoord.end()), yCoord.end());
    for(int i=1; i<=n; i++){
        L[i] = lower_bound(xCoord.begin(), xCoord.end(), L[i]) - xCoord.begin();
        R[i] = lower_bound(xCoord.begin(), xCoord.end(), R[i]) - xCoord.begin();
        D[i] = lower_bound(yCoord.begin(), yCoord.end(), D[i]) - yCoord.begin();
        U[i] = lower_bound(yCoord.begin(), yCoord.end(), U[i]) - yCoord.begin();
    }
    X = (int)xCoord.size()-1, Y = (int)yCoord.size()-1;
}

bool check1(){
    int maxX = 0, maxY = 0;
    for(int i=1; i<=n; i++) maxX = max(maxX, L[i]), maxY = max(maxY, D[i]);
    for(int i=1; i<=n; i++){
        if(maxX > R[i] || maxY > U[i]) return false;
    }
    ans.push_back(make_pair(maxX, maxY));
    return true;
}

struct namespace2{
    bool tryWith(int x, int y){
        int maxL = 1, maxD = 1, minR = X, minU = Y;
        for(int i=1; i<=n; i++){
            if(L[i] <= x && x <= R[i] && D[i] <= y && y <= U[i]) continue;
            maxL = max(maxL, L[i]), maxD = max(maxD, D[i]);
            minR = min(minR, R[i]), minU = min(minU, U[i]);
        }
        if(maxL <= minR && maxD <= minU){
            ans.push_back(make_pair(x, y));
            ans.push_back(make_pair(maxL, maxD));
            return true;
        }
        return false;
    }

    bool check2(){
        int maxL = *max_element(L+1, L+n+1);
        int minR = *min_element(R+1, R+n+1);
        int maxD = *max_element(D+1, D+n+1);
        int minU = *min_element(U+1, U+n+1);
        if(tryWith(maxL, maxD)) return true;
        if(tryWith(maxL, minU)) return true;
        if(tryWith(minR, maxD)) return true;
        if(tryWith(minR, minU)) return true;
        return false;
    }
} p2;

bool check2(){
    return p2.check2();
}

struct namespace3{
    bool check2(int n, vector<int> &L, vector<int> &R, vector<int> &D, vector<int> &U, int px, int py){
        int maxL = *max_element(L.begin(), L.end());
        int minR = *min_element(R.begin(), R.end());
        int maxD = *max_element(D.begin(), D.end());
        int minU = *min_element(U.begin(), U.end());
        int Xd[2] = {maxL, minR}, Yd[2] = {maxD, minU};
        for(int a: Xd) for(int b: Yd){
            int maxL = 1, maxD = 1, minR = X, minU = Y;
            for(int i=0; i<n; i++){
                if(L[i] <= a && a <= R[i] && D[i] <= b && b <= U[i]) continue;
                maxL = max(maxL, L[i]), maxD = max(maxD, D[i]);
                minR = min(minR, R[i]), minU = min(minU, U[i]);
            }
            if(maxL <= minR && maxD <= minU){
                ans.push_back(make_pair(px, py));
                ans.push_back(make_pair(a, b));
                ans.push_back(make_pair(maxL, maxD));
                return true;
            }
        }
        return false;
    }

    bool tryWith(int x, int y){
        vector<int> _L,_R,_D,_U;
        for(int i=1; i<=n; i++){
            if(L[i]<=x && x<=R[i] && D[i]<=y && y<=U[i]) continue;
            else _L.push_back(L[i]), _R.push_back(R[i]), _D.push_back(D[i]), _U.push_back(U[i]);
        }
        return check2((int)_L.size(),_L,_R,_D,_U,x,y);
    }

    bool check3(){
        int maxL = *max_element(L+1, L+n+1);
        int minR = *min_element(R+1, R+n+1);
        int maxD = *max_element(D+1, D+n+1);
        int minU = *min_element(U+1, U+n+1);
        if(tryWith(maxL, maxD)) return true;
        if(tryWith(maxL, minU)) return true;
        if(tryWith(minR, maxD)) return true;
        if(tryWith(minR, minU)) return true;
        return false;
    }

    bool tryWith(int x, int y, vector<int> &L, vector<int> &R, vector<int> &D, vector<int> &U, int px, int py){
        vector<int> _L,_R,_D,_U;
        for(int i=0; i<(int)L.size(); i++){
            if(L[i]<=x && x<=R[i] && D[i]<=y && y<=U[i]) continue;
            else _L.push_back(L[i]), _R.push_back(R[i]), _D.push_back(D[i]), _U.push_back(U[i]);
        }
        if(check2((int)_L.size(),_L,_R,_D,_U,x,y)){
            ans.push_back(make_pair(px, py));
            return true;
        }
        else return false;
    }

    bool check3(int n, vector<int> &L, vector<int> &R, vector<int> &D, vector<int> &U, int px, int py){
        int maxL = *max_element(L.begin(), L.end());
        int minR = *min_element(R.begin(), R.end());
        int maxD = *max_element(D.begin(), D.end());
        int minU = *min_element(U.begin(), U.end());
        if(tryWith(maxL, maxD, L, R, D, U, px, py)) return true;
        if(tryWith(maxL, minU, L, R, D, U, px, py)) return true;
        if(tryWith(minR, maxD, L, R, D, U, px, py)) return true;
        if(tryWith(minR, minU, L, R, D, U, px, py)) return true;
        return false;
    }
} p3;

bool check3(){
    return p3.check3();
}

struct namespace4{
    bool tryWith(int x, int y){
        vector<int> _L,_R,_D,_U;
        for(int i=1; i<=n; i++){
            if(L[i]<=x && x<=R[i] && D[i]<=y && y<=U[i]) continue;
            else _L.push_back(L[i]), _R.push_back(R[i]), _D.push_back(D[i]), _U.push_back(U[i]);
        }
        return p3.check3((int)_L.size(),_L,_R,_D,_U,x,y);
    }

    bool check4(){
        int maxL = *max_element(L+1, L+n+1);
        int minR = *min_element(R+1, R+n+1);
        int maxD = *max_element(D+1, D+n+1);
        int minU = *min_element(U+1, U+n+1);
        if(tryWith(maxL, maxD)) return true;
        if(tryWith(maxL, minU)) return true;
        if(tryWith(minR, maxD)) return true;
        if(tryWith(minR, minU)) return true;

        /// ���⼭���ʹ� �� ���� ��谡 ������ ���
        int l = minR, r = maxL, u = maxD, d = minU;
        assert(r - l >= 2 && u - d >= 2);

        int al = l+1, ar = r-1, cl = l+1, cr = r-1;
        int bl = d+1, br = u-1, dl = d+1, dr = u-1;
        int acl = al, acr = ar, bdl = bl, bdr = br;
        vector<pair<int, int> > ab, bc, cd, da;

        for(int i=1; i<=n; i++){
            int meetA = D[i] <= d && d <= U[i] && !(R[i] <= l || r <= L[i]);
            int meetB = L[i] <= l && l <= R[i] && !(U[i] <= d || u <= D[i]);
            int meetC = D[i] <= u && u <= U[i] && !(R[i] <= l || r <= R[i]);
            int meetD = L[i] <= r && r <= R[i] && !(U[i] <= d || u <= D[i]);

            if(meetA+meetB+meetC+meetD == 1){
                if(meetA) al = max(al, L[i]), ar = min(ar, R[i]);
                if(meetB) bl = max(bl, D[i]), br = min(br, U[i]);
                if(meetC) cl = max(cl, L[i]), cr = min(cr, R[i]);
                if(meetD) dl = max(dl, D[i]), dr = min(dr, U[i]);
            }
            else if(meetA+meetB+meetC+meetD == 2){
                if(meetA&&meetC) acl = max(acl, L[i]), acr = min(acr, R[i]);
                if(meetB&&meetD) bdl = max(bdl, D[i]), bdr = min(bdr, U[i]);
                if(meetA&&meetB) ab.push_back(make_pair(R[i], U[i]));
                if(meetC&&meetB) bc.push_back(make_pair(R[i], D[i]));
                if(meetC&&meetD) cd.push_back(make_pair(L[i], D[i]));
                if(meetA&&meetD) da.push_back(make_pair(L[i], U[i]));
            }
        }

        vector<int> aMaxB (X+2, Y), aMaxD (X+2, Y), cMinB (X+2, 1), cMinD (X+2, 1);
        for(pair<int, int> p: ab) aMaxB[p.first+1] = min(aMaxB[p.first+1], p.second);
        for(pair<int, int> p: da) aMaxD[p.first+1] = min(aMaxD[p.first+1], p.second);
        for(pair<int, int> p: bc) cMinB[p.first+1] = max(cMinB[p.first+1], p.second);
        for(pair<int, int> p: cd) cMinD[p.first+1] = max(cMinD[p.first+1], p.second);

        for(int a=l+1; a<r; a++) for(int c=l+1; c<r; c++){
            if((a<acl || a>acr) && (c<acl || c>acr)) continue;
            int bs = max(bl, cMinB[c]), be = min(br, aMaxB[a]);
            int ds = max(dl, cMinD[c]), de = min(dr, aMaxD[a]);
            if(bs <= be && ds <= de){
                int bans = -1, dans = -1;
                if(!(be < bdl && bdr < bs)) bans = max(bs, bdl), dans = ds;
                else if(!(de < bdl && bdr < ds)) dans = max(ds, bdl), bans = bs;
                else continue;
                assert(bans != -1 && dans != -1);
                assert(tryWith(l, bans));
                return true;
            }
        }

        return false;
    }
} p4;

bool check4(){
    return p4.check4();
}

void output(){
    if(ans.empty()) exit(1);
    while((int)ans.size() < k) ans.push_back(ans.back());
    for(auto p: ans) printf("%d %d\n", xCoord[p.first], yCoord[p.second]);
}

Compilation message

hamburg.cpp: In function 'void input()':
hamburg.cpp:26:10: warning: ignoring return value of 'int scanf(const char*, ...)' declared with attribute 'warn_unused_result' [-Wunused-result]
   26 |     scanf("%d %d", &n, &k);
      |     ~~~~~^~~~~~~~~~~~~~~~~
hamburg.cpp:28:14: warning: ignoring return value of 'int scanf(const char*, ...)' declared with attribute 'warn_unused_result' [-Wunused-result]
   28 |         scanf("%d %d %d %d", &L[i], &D[i], &R[i], &U[i]);
      |         ~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Subtask #1
1.0 / 1.0

# 결과 실행 시간 메모리 Grader output
1 Correct 2 ms 340 KB Output is correct
2 Correct 2 ms 340 KB Output is correct
3 Correct 2 ms 340 KB Output is correct
4 Correct 2 ms 340 KB Output is correct

Subtask #2
1.0 / 1.0

# 결과 실행 시간 메모리 Grader output
1 Correct 2 ms 340 KB Output is correct
2 Correct 2 ms 404 KB Output is correct
3 Correct 2 ms 340 KB Output is correct
4 Correct 2 ms 340 KB Output is correct

Subtask #3
3.0 / 3.0

# 결과 실행 시간 메모리 Grader output
1 Correct 2 ms 340 KB Output is correct
2 Correct 2 ms 340 KB Output is correct
3 Correct 2 ms 340 KB Output is correct
4 Correct 2 ms 340 KB Output is correct
5 Correct 2 ms 340 KB Output is correct
6 Correct 2 ms 340 KB Output is correct
7 Correct 2 ms 340 KB Output is correct
8 Correct 2 ms 340 KB Output is correct
9 Correct 2 ms 340 KB Output is correct
10 Correct 2 ms 340 KB Output is correct
11 Correct 2 ms 340 KB Output is correct
12 Correct 2 ms 340 KB Output is correct

Subtask #4
0 / 6.0

# 결과 실행 시간 메모리 Grader output
1 Correct 3 ms 340 KB Output is correct
2 Correct 2 ms 340 KB Output is correct
3 Correct 2 ms 340 KB Output is correct
4 Correct 2 ms 340 KB Output is correct
5 Correct 2 ms 340 KB Output is correct
6 Correct 2 ms 340 KB Output is correct
7 Correct 3 ms 340 KB Output is correct
8 Correct 3 ms 340 KB Output is correct
9 Correct 2 ms 404 KB Output is correct
10 Correct 3 ms 340 KB Output is correct
11 Correct 3 ms 340 KB Output is correct
12 Correct 2 ms 340 KB Output is correct
13 Correct 2 ms 340 KB Output is correct
14 Runtime error 8 ms 468 KB Execution failed because the return code was nonzero
15 Halted 0 ms 0 KB -

Subtask #5
1.0 / 1.0

# 결과 실행 시간 메모리 Grader output
1 Correct 2 ms 340 KB Output is correct
2 Correct 2 ms 340 KB Output is correct
3 Correct 2 ms 340 KB Output is correct
4 Correct 2 ms 340 KB Output is correct
5 Correct 249 ms 6696 KB Output is correct
6 Correct 245 ms 6776 KB Output is correct
7 Correct 239 ms 6700 KB Output is correct
8 Correct 242 ms 6776 KB Output is correct

Subtask #6
3.0 / 3.0

# 결과 실행 시간 메모리 Grader output
1 Correct 2 ms 340 KB Output is correct
2 Correct 2 ms 404 KB Output is correct
3 Correct 2 ms 340 KB Output is correct
4 Correct 2 ms 340 KB Output is correct
5 Correct 256 ms 6776 KB Output is correct
6 Correct 246 ms 6740 KB Output is correct
7 Correct 241 ms 6772 KB Output is correct
8 Correct 249 ms 6796 KB Output is correct

Subtask #7
6.0 / 6.0

# 결과 실행 시간 메모리 Grader output
1 Correct 2 ms 340 KB Output is correct
2 Correct 2 ms 340 KB Output is correct
3 Correct 2 ms 340 KB Output is correct
4 Correct 2 ms 340 KB Output is correct
5 Correct 2 ms 340 KB Output is correct
6 Correct 2 ms 340 KB Output is correct
7 Correct 2 ms 340 KB Output is correct
8 Correct 2 ms 340 KB Output is correct
9 Correct 2 ms 340 KB Output is correct
10 Correct 2 ms 340 KB Output is correct
11 Correct 2 ms 340 KB Output is correct
12 Correct 2 ms 340 KB Output is correct
13 Correct 251 ms 9332 KB Output is correct
14 Correct 257 ms 9476 KB Output is correct
15 Correct 253 ms 9468 KB Output is correct
16 Correct 252 ms 8788 KB Output is correct
17 Correct 255 ms 9488 KB Output is correct
18 Correct 248 ms 8020 KB Output is correct
19 Correct 251 ms 11132 KB Output is correct
20 Correct 281 ms 11532 KB Output is correct
21 Correct 271 ms 11132 KB Output is correct
22 Correct 258 ms 11512 KB Output is correct
23 Correct 274 ms 11380 KB Output is correct
24 Correct 270 ms 11256 KB Output is correct

Subtask #8
0 / 79.0

# 결과 실행 시간 메모리 Grader output
1 Correct 3 ms 340 KB Output is correct
2 Correct 2 ms 340 KB Output is correct
3 Correct 2 ms 340 KB Output is correct
4 Correct 2 ms 340 KB Output is correct
5 Correct 2 ms 340 KB Output is correct
6 Correct 2 ms 340 KB Output is correct
7 Correct 3 ms 340 KB Output is correct
8 Correct 3 ms 340 KB Output is correct
9 Correct 2 ms 404 KB Output is correct
10 Correct 3 ms 340 KB Output is correct
11 Correct 3 ms 340 KB Output is correct
12 Correct 2 ms 340 KB Output is correct
13 Correct 2 ms 340 KB Output is correct
14 Runtime error 8 ms 468 KB Execution failed because the return code was nonzero
15 Halted 0 ms 0 KB -