이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
// Success consists of going from failure to failure without loss of enthusiasm
#include <bits/stdc++.h>
using namespace std;
#define nl '\n'
#define pb push_back
template<class T> using V = vector<T>;
const int LG = 20;
int main() {
cin.tie(0)->sync_with_stdio(0);
// TIME TO IMPLEMENT FOR 40 MIN TO REALIZE THE IDEA IS WRONG!!
// (0-0)
int N, M; cin >> N >> M;
V<V<int>> adj(N); for(int e = 0; e < M; e++) {
int u, v; cin >> u >> v; --u, --v;
adj[u].pb(v);
adj[v].pb(u);
}
V<int> vis(N, 0), low(N, -1), disc(N, -1); int t = 0;
V<V<int>> good(N);
V<V<int>> up(N, V<int>(LG, -1));
auto jmp = [&](int u, int d) {
for(int i = 0; i < LG; i++) if ((d >> i) & 1) u = up[u][i];
return u;
};
auto lca = [&](int a, int b) {
if (disc[a] < disc[b]) swap(a, b);
a = jmp(a, disc[a] - disc[b]);
if (a == b) return a;
for(int i = LG - 1; i >= 0; i--) {
if (up[a][i] != up[b][i]) a = up[a][i], b = up[b][i];
}
return up[a][0];
};
V<int> stk = {-1};
function<void(int, int)> dfs = [&](int u, int p) {
cout << u << endl;
up[u][0] = (p == -1 ? u : p);
for(int i = 1; i < LG; i++) up[u][i] = up[up[u][i-1]][i-1];
vis[u] = 1;
disc[u] = ++t; stk.pb(u);
int best = -1;
sort(begin(adj[u]), end(adj[u]), [&](int x, int y) {
return disc[x] > disc[y];
});
for(auto& v : adj[u]) if (v != p) {
if (vis[v]) {
cout << u << " " << v << endl;
// back edge -> cycle
best = max(best, disc[v]);
} else {
low[v] = max(low[u], best);
dfs(v, u);
}
}
if (size(good[u])) {
for(auto x : good[u]) for(auto y : good[u]) if (x < y) {
cout << u << " " << x << " " << y << endl;
int l = lca(x, y);
if (max(low[x], low[y]) >= disc[l]) continue;
V<int> ans = {u};
int k = x;
while(k != l) {
ans.pb(k);
k = up[k][0];
}
ans.pb(l);
V<int> dwn;
k = y;
while(k != l) {
dwn.pb(k);
k = up[k][0];
}
dwn.pb(k);
dwn.pop_back(); reverse(begin(dwn), end(dwn));
for(auto c : dwn) ans.pb(c);
}
}
int len = disc[u] - best + 1;
int x = -1; for(auto& v : adj[u]) if (v != p) {
if (disc[v] == best) x = v;
}
if (low[u] < best) {
assert(x != -1);
cout << u << " -> " << x << endl;
if (len >= 4) {
while(stk.back() != x) { cout << stk.back() + 1 << " "; stk.pop_back(); }
cout << x + 1 << nl;
exit(0);
}
}
if (x != -1) good[x].pb(u);
--t; stk.pop_back();
};
dfs(0, -1);
cout << "no" << nl;
return (0-0);
}
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