제출 #786502

#제출 시각아이디문제언어결과실행 시간메모리
786502tr1ten은행 (IZhO14_bank)C++17
27 / 100
1085 ms12624 KiB
#include <cstdio> #include <bits/stdc++.h> using namespace std; #include "ext/pb_ds/assoc_container.hpp" #include "ext/pb_ds/tree_policy.hpp" using namespace __gnu_pbds; template<class T> using ordered_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update> ; template<typename T> using ordered_multiset = tree<T, null_type,less_equal<T>, rb_tree_tag,tree_order_statistics_node_update>; // find_by_order(k) returns iterator to kth element starting from 0; // order_of_key(k) returns count of elements strictly smaller than k; // useful defs typedef long long ll; typedef vector<ll> vi; typedef vector<vi> vii; typedef pair<ll,ll> pi; typedef vector<pi> vpi; typedef unordered_map<ll,ll> mll; #define pb push_back #define mp make_pair #define rep(i,a,b) for (int i = (a); i < (b); i++) #define per(i,a,b) for (int i = (b)-1; i >= (a); i--) #define trav(a,arr) for (auto& a: (arr)) #define sz(x) (int)(x).size() #define mk_vec(name,sz,value) vi name(sz,value) #define mk_mat(name,n,m,value) vii name(n, vi(m, value)) #define contains(x) find(x) != string::npos #define tkv(vec,sz) rep(i,0,sz) cin>>vec[i] #define srv(vec) sort(vec.begin(), vec.end()) #define all(x) x.begin(), x.end() #define less(a,b) a<b #define vsum(vec) accumulate(vec.begin(), vec.end(), 0L); #define vmax(vec) *max_element(vec.begin(), vec.end()); #define vmin(vec) *min_element(vec.begin(), vec.end()); #define pvc(vec) trav(x,vec) cout<<x<<" "; cout<<endl; #define put(x) cout<<(x)<<endl; #define put2(x,y) cout<<(x)<<" "<<(y)<<endl; #define put3(x,y,z) cout<<(x)<<" "<<(y)<<" "<<(z)<<endl; #define mod(x) (x + MOD)%MOD // debugging #define timed(x) {auto start = chrono::steady_clock::now(); x; auto end = chrono::steady_clock::now(); auto diff = end - start; cout << chrono::duration <double, milli> (diff).count() << " ms" << endl;} void __print(int x) {cerr << x;} void __print(long x) {cerr << x;} void __print(long long x) {cerr << x;} void __print(unsigned x) {cerr << x;} void __print(unsigned long x) {cerr << x;} void __print(unsigned long long x) {cerr << x;} void __print(float x) {cerr << x;} void __print(double x) {cerr << x;} void __print(long double x) {cerr << x;} void __print(char x) {cerr << '\'' << x << '\'';} void __print(const char *x) {cerr << '\"' << x << '\"';} void __print(const string &x) {cerr << '\"' << x << '\"';} void __print(bool x) {cerr << (x ? "true" : "false");} template<typename T, typename V> void __print(const pair<T, V> &x) {cerr << '{'; __print(x.first); cerr << ','; __print(x.second); cerr << '}';} template<typename T> void __print(const T &x) {int f = 0; cerr << '{'; for (auto &i: x) cerr << (f++ ? "," : ""), __print(i); cerr << "}";} void _print() {cerr << "]\n";} template <typename T, typename... V> void _print(T t, V... v) {__print(t); if (sizeof...(v)) cerr << ", "; _print(v...);} #ifndef ONLINE_JUDGE #define debug(x...) cerr << "[" << #x << "] = ["; _print(x) #else #define debug(x...) #endif const ll MOD = 1e9+7; const ll INF = 1e10+5; vi amt; // pre cal cost of each mask vi A; vi B; inline int pct(int x){ return __builtin_popcount(x);} void rec(vector<int> &nt,int idx,int t_mask,int mask,int target,int *dp){ if(idx==(int)nt.size()) { int ans = dp[mask] | 1<<target; if(amt[t_mask] == A[target] && pct(dp[mask | t_mask]) < pct(ans)) { dp[mask | t_mask] = ans; } return; } rec(nt,idx+1,t_mask,mask,target,dp); if(A[target] - amt[t_mask | 1<<nt[idx]] >=0) rec(nt,idx+1,t_mask | 1<<nt[idx],mask,target,dp); } // driver code int main() { ios_base::sync_with_stdio(false); cin.tie(nullptr); // freopen("input.in","r",stdin); // freopen("output.out","w",stdout); int T=1; // cin>>T; while(T--){ int n,m; cin >> n >> m; A.resize(n); tkv(A,n); B.resize(m); tkv(B,m); amt.resize(1<<m); rep(mask,0,1<<m){ ll sm = 0; rep(i,0,m){ if((mask&(1<<i))) sm += B[i]; } amt[mask] = sm; } int dp[1<<m]; // max mask of people it can give slary to memset(dp,0,sizeof dp); rep(mask,0,1<<m){ vector<int> nt; rep(i,0,m){ if((mask&(1<<i))==0) nt.push_back(i); } rep(j,0,n){ if(dp[mask]&(1<<j)) continue; // already paid; rec(nt,0,0,mask,j,dp); } } if(dp[(1<<m) - 1] == (1<<n) - 1) put("YES") else put("NO") } return 0; }
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