이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <cstdio>
#include <bits/stdc++.h>
using namespace std;
#include "ext/pb_ds/assoc_container.hpp"
#include "ext/pb_ds/tree_policy.hpp"
using namespace __gnu_pbds;
template<class T>
using ordered_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update> ;
template<typename T>
using ordered_multiset = tree<T, null_type,less_equal<T>, rb_tree_tag,tree_order_statistics_node_update>;
// find_by_order(k) returns iterator to kth element starting from 0;
// order_of_key(k) returns count of elements strictly smaller than k;
// useful defs
typedef long long ll;
typedef vector<ll> vi;
typedef vector<vi> vii;
typedef pair<ll,ll> pi;
typedef vector<pi> vpi;
typedef unordered_map<ll,ll> mll;
#define pb push_back
#define mp make_pair
#define rep(i,a,b) for (int i = (a); i < (b); i++)
#define per(i,a,b) for (int i = (b)-1; i >= (a); i--)
#define trav(a,arr) for (auto& a: (arr))
#define sz(x) (int)(x).size()
#define mk_vec(name,sz,value) vi name(sz,value)
#define mk_mat(name,n,m,value) vii name(n, vi(m, value))
#define contains(x) find(x) != string::npos
#define tkv(vec,sz) rep(i,0,sz) cin>>vec[i]
#define srv(vec) sort(vec.begin(), vec.end())
#define all(x) x.begin(), x.end()
#define less(a,b) a<b
#define vsum(vec) accumulate(vec.begin(), vec.end(), 0L);
#define vmax(vec) *max_element(vec.begin(), vec.end());
#define vmin(vec) *min_element(vec.begin(), vec.end());
#define pvc(vec) trav(x,vec) cout<<x<<" "; cout<<endl;
#define put(x) cout<<(x)<<endl;
#define put2(x,y) cout<<(x)<<" "<<(y)<<endl;
#define put3(x,y,z) cout<<(x)<<" "<<(y)<<" "<<(z)<<endl;
#define mod(x) (x + MOD)%MOD
// debugging
#define timed(x) {auto start = chrono::steady_clock::now(); x; auto end = chrono::steady_clock::now(); auto diff = end - start; cout << chrono::duration <double, milli> (diff).count() << " ms" << endl;}
void __print(int x) {cerr << x;}
void __print(long x) {cerr << x;}
void __print(long long x) {cerr << x;}
void __print(unsigned x) {cerr << x;}
void __print(unsigned long x) {cerr << x;}
void __print(unsigned long long x) {cerr << x;}
void __print(float x) {cerr << x;}
void __print(double x) {cerr << x;}
void __print(long double x) {cerr << x;}
void __print(char x) {cerr << '\'' << x << '\'';}
void __print(const char *x) {cerr << '\"' << x << '\"';}
void __print(const string &x) {cerr << '\"' << x << '\"';}
void __print(bool x) {cerr << (x ? "true" : "false");}
template<typename T, typename V>
void __print(const pair<T, V> &x) {cerr << '{'; __print(x.first); cerr << ','; __print(x.second); cerr << '}';}
template<typename T>
void __print(const T &x) {int f = 0; cerr << '{'; for (auto &i: x) cerr << (f++ ? "," : ""), __print(i); cerr << "}";}
void _print() {cerr << "]\n";}
template <typename T, typename... V>
void _print(T t, V... v) {__print(t); if (sizeof...(v)) cerr << ", "; _print(v...);}
#ifndef ONLINE_JUDGE
#define debug(x...) cerr << "[" << #x << "] = ["; _print(x)
#else
#define debug(x...)
#endif
const ll MOD = 1e9+7;
const ll INF = 1e10+5;
vi amt; // pre cal cost of each mask
vi A;
vi B;
inline int pct(int x){ return __builtin_popcount(x);}
void rec(vector<int> &nt,int idx,int t_mask,int mask,int target,int *dp){
if(idx==(int)nt.size()) {
int ans = dp[mask] | 1<<target;
if(amt[t_mask] == A[target] && pct(dp[mask | t_mask]) < pct(ans)) {
dp[mask | t_mask] = ans;
}
return;
}
rec(nt,idx+1,t_mask,mask,target,dp);
if(A[target] - amt[t_mask | 1<<nt[idx]] >=0) rec(nt,idx+1,t_mask | 1<<nt[idx],mask,target,dp);
}
// driver code
int main()
{
ios_base::sync_with_stdio(false);
cin.tie(nullptr);
// freopen("input.in","r",stdin);
// freopen("output.out","w",stdout);
int T=1;
// cin>>T;
while(T--){
int n,m;
cin >> n >> m;
A.resize(n);
tkv(A,n);
B.resize(m);
tkv(B,m);
amt.resize(1<<m);
rep(mask,0,1<<m){
ll sm = 0;
rep(i,0,m){
if((mask&(1<<i))) sm += B[i];
}
amt[mask] = sm;
}
int dp[1<<m]; // max mask of people it can give slary to
memset(dp,0,sizeof dp);
rep(mask,0,1<<m){
vector<int> nt;
rep(i,0,m){
if((mask&(1<<i))==0) nt.push_back(i);
}
rep(j,0,n){
if(dp[mask]&(1<<j)) continue; // already paid;
rec(nt,0,0,mask,j,dp);
}
}
if(dp[(1<<m) - 1] == (1<<n) - 1) put("YES")
else put("NO")
}
return 0;
}
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