제출 #785910

#제출 시각아이디문제언어결과실행 시간메모리
785910blackslex사이버랜드 (APIO23_cyberland)C++17
15 / 100
1492 ms108944 KiB
#include<bits/stdc++.h> #include "cyberland.h" using namespace std; using pid = pair<int, double>; using tp = tuple<double, int, int, int>; const int N = 1e5 + 5, K = 75; double d[N][K][2], ans; vector<pid> v[N]; bool f[N][K][2]; double solve(int n, int m, int k, int h, std::vector<int> x, std::vector<int> y, std::vector<int> c, std::vector<int> arr) { k = min(k, 67), ans = 1e11; priority_queue<tp, vector<tp>, greater<tp>> q; for (int i = 0; i <= n; i++) v[i].clear(); for (int i = 0; i < m; i++) v[x[i]].emplace_back(y[i], c[i]), v[y[i]].emplace_back(x[i], c[i]); for (int i = 0; i <= n; i++) for (int j = 0; j <= k; j++) d[i][j][0] = d[i][j][1] = 1e11, f[i][j][0] = f[i][j][1] = 0; q.emplace(d[h][0][0] = 0, h, 0, 0); while (!q.empty()) { auto [nd, nn, nsa, nsb] = q.top(); q.pop(); if (f[nn][nsa][nsb]) continue; f[nn][nsa][nsb] = 1; for (auto &[tn, td]: v[nn]) { double nds = nd + (nsb ? 0 : td / pow((double) 2, nsa)); if (d[tn][nsa][nsb] > nds) q.emplace(d[tn][nsa][nsb] = nds, tn, nsa, nsb); } if (!arr[nn]) for (auto &[tn, td]: v[nn]) if (d[tn][nsa][!nsb] > nd) q.emplace(d[tn][nsa][!nsb] = nd, tn, nsa, !nsb); if (nsa < k && arr[nn] == 2) { for (auto &[tn, td]: v[nn]) { double nds = nd + (nsb ? 0 : td / pow((double) 2, nsa + 1)); if (d[tn][nsa][nsb] > nds) q.emplace(d[tn][nsa][nsb] = nds, tn, nsa + 1, nsb); } } } for (int i = 0; i <= k; i++) for (int j = 0; j < 2; j++) ans = min(ans, d[0][i][j]); return (ans == 1e11 ? -1 : ans); }

컴파일 시 표준 에러 (stderr) 메시지

cyberland.cpp: In function 'double solve(int, int, int, int, std::vector<int>, std::vector<int>, std::vector<int>, std::vector<int>)':
cyberland.cpp:22:9: warning: this 'if' clause does not guard... [-Wmisleading-indentation]
   22 |         if (f[nn][nsa][nsb]) continue; f[nn][nsa][nsb] = 1;
      |         ^~
cyberland.cpp:22:40: note: ...this statement, but the latter is misleadingly indented as if it were guarded by the 'if'
   22 |         if (f[nn][nsa][nsb]) continue; f[nn][nsa][nsb] = 1;
      |                                        ^
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