# | 제출 시각UTC-0 | 아이디 | 문제 | 언어 | 결과 | 실행 시간 | 메모리 |
---|---|---|---|---|---|---|---|
785900 | canadavid1 | Teleporters (IOI08_teleporters) | C++14 | 503 ms | 50476 KiB |
이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
using i64 = int64_t;
#define all(x) begin(x),end(x)
/*
Idea:
traverse without any added
enumerate and group up unreachable regions
need only count of number of teles in each region
only 2(teleporters)+1 states, changing takes exactly one teleport => optimal 2(n+m) points
any new teleporter added can only increase region count by 2, and should ideally connect a reachable and unreachable
section together (this makes the unreachable section a "subroutine" at the other point)
*/
// adding each teleporter:
// if both endpoints are the same group, partition the group into "inside" and "outside"
// if enpoints are different, the ends become the same group
// sounds like union find
// size of the path. Made smaller for debugging purposes. Should be strictly bigger than the last paths end.
#define PATHLEN 2000010
signed main()
{
int N,M;
cin >> N >> M;
vector<pair<int,int>> tele(N);
for(int i = 0; i < N; i++) cin >> tele[i].first >> tele[i].second;
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