Submission #785288

#	Time	Username	Problem	Language	Result	Execution time	Memory
785288		makanhulia	Global Warming (CEOI18_glo)	C++17	15 / 100	181 ms	15900 KiB

glo

#include <bits/stdc++.h>
using namespace std;
 
#define v          vector
#define int        long long
#define all(a)     (a).begin(), (a).end()
#define pb         push_back
#define mk         make_pair
#define pii        pair<int, int>
#define ff         first
#define ss         second
#define inp_v(vec) for (auto &i : vec) cin >> i;
#define prt_v(vec) for (auto i : vec) cout << i << endl;
#define MS(x)     memset(x, 0, sizeof(x))
#define gcd(a,b)   __gcd(a, b);
#define lcm(a,b)   (a*(b/gcd(a,b)))
bool chmin(int &a, int b){return b<a?a=b, true:false;}
bool chmax(int &a, int b){return b>a?a=b, true:false;}
const int maxn=2e5+5;
int N, x;
int ans=1;

void cek(vector<int>A2){
    int dpp[N+1];
    for(int i=1;i<=N;i++){
        dpp[i]=1;
    }
    for(int i=2;i<=N;i++){
        for(int j=i-1;j>=1;j--){
            if(A2[i]>A2[j])dpp[i]=max(dpp[i], dpp[j]+1);
        }
        ans=max(ans, dpp[i]);
    }
    return;
}
signed main(){
    ios_base::sync_with_stdio(false); cin.tie(0);
    cin>>N>>x;
    vector<int>A(N+1), dp(N+1);
    for(int i=1;i<=N;i++)cin>>A[i];
    if(N<=50){
        for(int i=1;i<=N;i++){
            for(int k=-x;k<=x;k++){
                auto temp=A;
                for(int j=i;j<=N;j++){
                    temp[j]+=k;
                    // for(auto isi:temp)cout<<isi<<" ";
                    // cout<<endl;
                    cek(temp);
                }
            }
        }
        cout<<ans<<endl;
        
    }
    else if(!x){
        multiset<pair<int, int>>st;
        dp[N]=1;
        st.insert({A[N], 1});
        int ans=1;
        for(int i=N-1;i>=1;i--){
            auto it=st.upper_bound({A[i], 0});
            if(it==st.end())dp[i]=1;
            else{
                dp[i]=(*it).second+1;
            }     
            ans=max(ans, dp[i]);
            auto lb=st.lower_bound({A[i], 0});
            if(lb!=st.end()&&(*lb).first==A[i])st.erase(lb);
            st.insert({A[i], dp[i]});
        }
        cout<<ans<<endl;
    }
    return 0;
}

• Subtask 1: 5 / 5
• Subtask 2: 10 / 10
• Subtask 3: 0 / 13
• Subtask 4: 0 / 10
• Subtask 5: 0 / 20
• Subtask 6: 0 / 17
• Subtask 7: 0 / 25